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What are POD types in C++?
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As I understand POD (PlainOldData) is just a raw data - it does not need:
to be constructed,
to be destroyed,
to have custom operators.
Must not have virtual functions,
and must not override operators.
How to check if something is a POD? Well, there is a struct for ...
What is the difference between Raising Exceptions vs Throwing Exceptions in Ruby?
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How do I break a string across more than one line of code in JavaScript?
Is there a character in JavaScript to break up a line of code so that it is read as continuous despite being on a new line?
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How do I use PHP namespaces with autoload?
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How does the algorithm to color the song list in iTunes 11 work? [closed]
...as suitable... looks like I reinvented the wheel a bit here)
convertToYUV[rawRGB_] :=
Module[{yuv},
yuv = {{0.299, 0.587, 0.114}, {-0.14713, -0.28886, 0.436},
{0.615, -0.51499, -0.10001}};
yuv . rawRGB
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Next, I wrote a function to calculate color distance with...
Load RSA public key from file
...ng with Public and private keys.
The der format can be obtained but saving raw data ( without encoding base64).
I hope this helps programmers.
import java.io.ByteArrayOutputStream;
import java.io.DataInputStream;
import java.io.DataOutputStream;
import java.io.File;
import java.io.FileInputStream;
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Is “argv[0] = name-of-executable” an accepted standard or just a common convention?
...inal question - I have no operating system. I'm writing code to build the raw argc/argv buffer for an executable loaded onto an embedded device and needed to know what I should do with argv[0]). +1 to StackOverflow for being awesome!
– Mike Willekes
Jan 13 '1...
The application was unable to start correctly (0xc000007b)
I have a client/server app which I have been developing on a single PC. Now it needs two serial ports, so I borrowed a PC from a friend.
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How are Python's Built In Dictionaries Implemented?
...one know how the built in dictionary type for python is implemented? My understanding is that it is some sort of hash table, but I haven't been able to find any sort of definitive answer.
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