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Is there a way to check which CSS styles are being used or not used on a web page?
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Would be awesome to see which ones are used as well.... but this is great, thanks.
– Serj Sagan
Mar 11 '17 at 6:18
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Sleep until a specific time/date
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As mentioned by Outlaw Programmer, I think the solution is just to sleep for the correct number of seconds.
To do this in bash, do the following:
current_epoch=$(date +%s)
target_epoch=$(date -d '01/01/2010 12:00' +%s)
sleep_secon...
Cleanest way to get last item from Python iterator
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Why the placeholder "defaultvalue"? Why not None? This is precisely what None is for. Are you suggesting that some function-specific default value could even be correct? If the iterator doesn't actually iterate, then an out-of-band value is more meaningful than some ...
Check if multiple strings exist in another string
...e a is a list of strings, and x is an element of that list, x is a string (one of 'a', 'b', 'c' in original example)
– User
Jan 27 '14 at 20:50
6
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Credit card expiration dates - Inclusive or exclusive?
...rite your own credit card processing code. If^H^HWhen you write a bug, someone will lose real money. We all make mistakes, just don't make decisions that turn your mistakes into catastrophes.
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Link to the issue number on GitHub within a commit message
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In which situations shall each one be used?
– nilsi
Feb 26 '13 at 17:34
1
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How to implement history.back() in angular.js
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But i have 2 buttons in my header one for home and one for back if i understand your code the element in the link function is the element that was clicked in that case history.back will apply also for home button?(which is not good)
– ba...
Get fully qualified class name of an object in Python
...name__
# in Python 3.
module = o.__class__.__module__
if module is None or module == str.__class__.__module__:
return o.__class__.__name__ # Avoid reporting __builtin__
else:
return module + '.' + o.__class__.__name__
bar = foo.Bar()
print fullname(bar)
and Bar defined as
class...
Sorting arrays in NumPy by column
...e:
In [6]: a.view('i8,i8,i8').sort(order=['f1'], axis=0) #<-- returns None
In [7]: a
Out[7]:
array([[0, 0, 1],
[1, 2, 3],
[4, 5, 6]])
@Steve's really is the most elegant way to do it, as far as I know...
The only advantage to this method is that the "order" argument is a list...
Equivalent of Math.Min & Math.Max for Dates?
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this seemed to me to be closest to a one line replacement/equivalent for Math.Min but the other answers were great too, for completeness
– hawbsl
Jan 4 '10 at 10:07
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