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How to replace a set of tokens in a Java String?
I have the following template String: "Hello [Name] Please find attached [Invoice Number] which is due on [Due Date]" .
15...
How to extract base URL from a string in JavaScript?
I'm trying to find a relatively easy and reliable method to extract the base URL from a string variable using JavaScript (or jQuery).
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How to install a node.js module without using npm?
... page but are not published with the npm-registry. These modules can't be installed using npm.
5 Answers
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What does it mean to start a PHP function with an ampersand?
I'm using the Facebook library with this code in it:
3 Answers
3
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How to deal with SQL column names that look like SQL keywords?
...I can't change the name because I didn't make it.
Am I allowed to do something like SELECT from FROM TableName or is there a special syntax to avoid the SQL Server being confused?
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SVN needs-lock 设置强制只读属性（官方资料） - 环境配置 - 清泛IT论坛，...
...om SubversionWiki
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Different versions of binary files cannot be merged. Therefore versioning of binary files should follow the lock-modify-unlock model[1]. This setup uses the following three measuresforces users to use property svn:needs-lock on newly added binary f...
Java OCR implementation [closed]
This is primarily just curiosity, but are there any OCR implementations in pure Java? I'm curious how this would perform purely in Java, and OCR in general interests me, so I'd love to see how it's implemented in a language I thoroughly understand. Naturally, this would require that the implementati...
Learning Regular Expressions [closed]
I don't really understand regular expressions. Can you explain them to me in an easy-to-follow manner? If there are any online tools or books, could you also link to them?
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Resharper- Find all unused classes
I know how to find unused references of a single file by right clicking on the file and selecting the "Find Usages" option. Is there any way I can see or get the list of all the unused classes or files in my project ?
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Return index of greatest value in an array
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This is probably the best way, since it’s reliable and works on old browsers:
function indexOfMax(arr) {
if (arr.length === 0) {
return -1;
}
var max = arr[0];
var maxIndex = 0;
for (var i = 1; i < arr.length; i++) {
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