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CSS last-child selector: select last-element of specific class, not last child inside of parent?
...f .comment.
body {
background: black;
}
.comment {
width: 470px;
border-bottom: 1px dotted #f0f0f0;
margin-bottom: 10px;
}
.comment:last-of-type {
border-bottom: none;
margin-bottom: 0;
}
<div class="commentList">
<article class="comment " id="com21">&...
Does Ruby regular expression have a not match operator like “!~” in Perl?
... from the documentation page of Regexp. Nevertheless, it works:
irb(main):001:0> 'x' !~ /x/
=> false
irb(main):002:0> 'x' !~ /y/
=> true
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Will using goto leak variables?
...
210
Warning: This answer pertains to C++ only; the rules are quite different in C.
Won't x be ...
How to get the index of a maximum element in a numpy array along one axis
...
>>> a.argmax(axis=0)
array([1, 1, 0])
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How to parse Excel (XLS) file in Javascript/HTML5
...he function.
<script src="https://cdnjs.cloudflare.com/ajax/libs/xlsx/0.8.0/jszip.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/xlsx/0.8.0/xlsx.js"></script>
<script>
var ExcelToJSON = function() {
this.parseExcel = function(file) {
var read...
How to get the caret column (not pixels) position in a textarea, in characters, from the start?
...return node.selectionStart;
} else if (!document.selection) {
return 0;
}
var c = "\001",
sel = document.selection.createRange(),
dul = sel.duplicate(),
len = 0;
dul.moveToElementText(node);
sel.text = c;
len = dul.text.indexOf(c);
sel.moveStart('character',-1);...
Ruby Gem install Json fails on Mavericks and Xcode 5.1 - unknown argument: '-multiply_definedsuppres
...
10 Answers
10
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Creating a new column based on if-elif-else condition
...
140
To formalize some of the approaches laid out above:
Create a function that operates on the rows...
SQL statement to select all rows from previous day
...rom one table. The table holds one datetime column. I am using SQL Server 2005.
11 Answers
...
LINQ with groupby and count
... .OrderBy(x => x.Metric))
{
Console.WriteLine("{0} {1}", line.Metric, line.Count);
}
> This was a brilliantly quick reply but I'm having a bit of an issue with the first line, specifically "data.groupby(info=>info.metric)"
I'm assuming you already have a list/array...