大约有 45,000 项符合查询结果(耗时:0.0978秒) [XML]
Best way to check if UITableViewCell is completely visible
I have a UITableView with cells of different heights and I need to know when they are completely visible or not.
10 Answe...
Check if Key Exists in NameValueCollection
Is there a quick and simple way to check if a key exists in a NameValueCollection without looping through it?
12 Answers
...
Determine if an element has a CSS class with jQuery
I'm working with jQuery and looking to see if there is an easy way to determine if the element has a specific CSS class associated with it.
...
HTML5 check if audio is playing?
What's the javascript api for checking if an html5 audio element is currently playing?
9 Answers
...
Checking if a string array contains a value, and if so, getting its position
...4" };
string value = "text3";
int pos = Array.IndexOf(stringArray, value);
if (pos > -1)
{
// the array contains the string and the pos variable
// will have its position in the array
}
share
|
...
JavaScript null check
...
An “undefined variable” is different from the value undefined.
An undefined variable:
var a;
alert(b); // ReferenceError: b is not defined
A variable with the value undefined:
var a;
alert(a); // Alerts “undefined”
When a function takes an ar...
How to break out of nested loops?
If I use a break statement, it will only break inner loop and I need to use some flag to break the outer loop. But if there are many nested loops, the code will not look good.
...
The 3 different equals
What is the difference between = , == , and === ?
5 Answers
5
...
Do something if screen width is less than 960 px
How can I make jQuery do something if my screen width is less than 960 pixels? The code below always fires the 2nd alert, regardless of my window size:
...
Replace values in list using Python [duplicate]
...
Build a new list with a list comprehension:
new_items = [x if x % 2 else None for x in items]
You can modify the original list in-place if you want, but it doesn't actually save time:
items = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
for index, item in enumerate(items):
if not (item ...
