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Add a column to a table, if it does not already exist
...an use a similar construct by using the sys.columns table io sys.objects.
IF NOT EXISTS (
SELECT *
FROM sys.columns
WHERE object_id = OBJECT_ID(N'[dbo].[Person]')
AND name = 'ColumnName'
)
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How to split one string into multiple variables in bash shell? [duplicate]
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If your solution doesn't have to be general, i.e. only needs to work for strings like your example, you could do:
var1=$(echo $STR | cut -f1 -d-)
var2=$(echo $STR | cut -f2 -d-)
I chose cut here because you could simply ex...
How to check if NSString begins with a certain character
How do you check if an NSString begins with a certain character (the character *).
10 Answers
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Angularjs ng-model doesn't work inside ng-if
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The ng-if directive, like other directives creates a child scope. See the script below (or this jsfiddle)
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.0rc1/angular.min.js"></script>
<script...
Programmatically Lighten or Darken a hex color (or rgb, and blend colors)
... was working on to programmatically lighten or darken a hex color by a specific amount. Just pass in a string like "3F6D2A" for the color ( col ) and a base10 integer ( amt ) for the amount to lighten or darken. To darken, pass in a negative number (i.e. -20 ).
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How to capitalize the first character of each word in a string
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WordUtils.capitalize(str) (from apache commons-text)
(Note: if you need "fOO BAr" to become "Foo Bar", then use capitalizeFully(..) instead)
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Is it possible to determine whether ViewController is presented as Modal?
....presentingViewController isKindOfClass:[UITabBarController class]];
}
Swift:
var isModal: Bool {
return self.presentingViewController?.presentedViewController == self
|| (self.navigationController != nil && self.navigationController?.presentingViewController?.presentedViewCon...
javascript set a variable if undefined
I know that I can test for a javascript variable and then define it if it is undefined, but is there not some way of saying
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Testing if jQueryUI has loaded
...te, and I think that jQueryUI may not have loaded properly. How can I test if jQueryUI has loaded?
5 Answers
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Efficient way to remove keys with empty strings from a dict
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Python 2.X
dict((k, v) for k, v in metadata.iteritems() if v)
Python 2.7 - 3.X
{k: v for k, v in metadata.items() if v is not None}
Note that all of your keys have values. It's just that some of those values are the empty string. There's no such thing as a key in a dict w...