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Interface defining a constructor signature?
...or within an interface, you'd have trouble deriving classes:
public class Foo : IParameterlessConstructor
{
public Foo() // As per the interface
{
}
}
public class Bar : Foo
{
// Yikes! We now don't have a parameterless constructor...
public Bar(int x)
{
}
}
...
Why start a shell command with a backslash?
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Aren't Python strings immutable? Then why does a + “ ” + b work?
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The variable, a, which points to the string, is mutable.
Consider:
a = "Foo"
# a now points to "Foo"
b = a
# b points to the same "Foo" that a points to
a = a + a
# a points to the new string "FooFoo", but b still points to the old "Foo"
print a
print b
# Outputs:
# FooFoo
# Foo
# Observe that...
What is the difference between const int*, const int * const, and int const *?
...are clear on the meaning of const:
int a = 5, b = 10, c = 15;
const int* foo; // pointer to constant int.
foo = &a; // assignment to where foo points to.
/* dummy statement*/
*foo = 6; // the value of a can´t get changed through the pointer.
foo = &b; /...
How much is too much with C++11 auto keyword?
...us to the reader what type auto represents.
Here are some examples:
auto foo = std::make_shared<Foo>(); // obvious
auto foo = bla(); // unclear. don't know which type `foo` has
const size_t max_size = 100;
for ( auto x = max_size; x > 0; --x ) // unclear. could lead...
Overloaded method selection based on the parameter's real type
...s used to determine the signature of the method to be called, in this case foo(Object). At runtime, the class of the object the method is called on determines which implementation of that method is called, taking into account that it may be an instance of a subclass of the declared type that overrid...
Merge git repo into branch of another repo
Given repo Foo and repo Bar. I want to merge Bar with Foo, but only into a separate branch, called baz .
3 Answers
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Python using enumerate inside list comprehension
Lets suppose I have a list like this:
7 Answers
7
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What does the arrow operator, '->', do in Java?
While hunting through some code I came across the arrow operator, what exactly does it do? I thought Java did not have an arrow operator.
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Static function variables in Swift
... class/struct. Try declaring a private struct with static variable.
func foo() -> Int {
struct Holder {
static var timesCalled = 0
}
Holder.timesCalled += 1
return Holder.timesCalled
}
7> foo()
$R0: Int = 1
8> foo()
$R1: Int = 2
9> foo()
$R2: Int = 3
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