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Split (explode) pandas dataframe string entry to separate rows
... for _, row in a.iterrows()]).reset_index()
Out[55]:
index 0
0 a 1
1 b 1
2 c 1
3 d 2
4 e 2
5 f 2
Then you just have to rename the columns
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Why do Lua arrays(tables) start at 1 instead of 0?
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Although I too found them weird at the beginning, I have learned to love 0-based arrays. But I get by OK with Lua's 1-based arrays, especially by
using Lua's generic for loop and the ipairs operator—I can usually avoid worrying about just how arrays are indexed.
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Generate random number between two numbers in JavaScript
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edited Jun 12 '19 at 12:06
Luca Fagioli
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What Process is using all of my disk IO
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You're looking for iotop (assuming you've got kernel >2.6.20 and Python 2.5). Failing that, you're looking into hooking into the filesystem. I recommend the former.
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Regex group capture in R with multiple capture-groups
...roup in the match (and one for the whole match):
> s = c("(sometext :: 0.1231313213)", "(moretext :: 0.111222)")
> str_match(s, "\\((.*?) :: (0\\.[0-9]+)\\)")
[,1] [,2] [,3]
[1,] "(sometext :: 0.1231313213)" "sometext" "0.1231313213"
[2,] "(moretex...
Remove insignificant trailing zeros from a number?
... first place since it was created as a Number, not a String.
var n = 1.245000
var noZeroes = n.toString() // "1.245"
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Clojure 1.2.1/1.3/1.4 'proxy generated in Grails 2.0.0 runtime fails. 1.2.0 is fine
I'm working on extending the Grails Clojure plugin in Grails 2.0.0 (and 2.1.0-SNAPSHOT) and I wanted to update it to Clojure 1.3.0 and add clojure.tools.logging .
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Detect if value is number in MySQL
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answered Feb 21 '11 at 10:47
RichardTheKiwiRichardTheKiwi
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What is the JavaScript >>> operator and how do you use it?
...doing a bitwise operation with no actual effect, like a rightward-shift of 0 bits >>0, is a quick way to round a number and ensure it is in the 32-bit int range. Additionally, the triple >>> operator, after doing its unsigned operation, converts the results of its calculation to Numbe...
Understanding “randomness”
...ough a pseudo-random variable:
BarChart[BinCounts[RandomReal[{0, 1}, 50000], 0.01]]
While this is the distribution you get after multiplying two random variables:
BarChart[BinCounts[Table[RandomReal[{0, 1}, 50000] *
RandomReal[{0, 1}, 500...