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Is it possible to use the SELECT INTO clause with UNION [ALL]?
In SQL Server this inserts 100 records, from the Customers table into tmpFerdeen :-
8 Answers
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使用App Inventor扩展实现多点触控：Scale Detector · App Inventor 2 中文网
...or.aix 扩展。 该扩展包含在源代码中。 通常，项目源文件包括项目使用的任何扩展名。
2、实现ScaleDetector扩展
上一节展示了如何使用提供的 ScaleDetector 扩展 aix 文件创建应用程序。 你还可以练习实现扩展本身。
规模检测或扩...
GROUP BY with MAX(DATE) [duplicate]
...'s answer will tend to perform less I/O. The analytic function allows the SQL to process the the table in a single pass, whereas Oliver's solution requires multiple passes.
– Adam Musch
Aug 16 '10 at 14:33
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Rename MySQL database [duplicate]
.... Now I need to change database name to sunhrm . But, It is disabled in MySQL workbench. Can I do that on the Linux server itself?
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Why does Oracle 9i treat an empty string as NULL?
...at doesn't do much to tell me why this is the case. As I understand the SQL specifications, ' ' is not the same as NULL -- one is a valid datum, and the other is indicating the absence of that same information.
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How to get last inserted id?
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For SQL Server 2005+, if there is no insert trigger, then change the insert statement (all one line, split for clarity here) to this
INSERT INTO aspnet_GameProfiles(UserId,GameId)
OUTPUT INSERTED.ID
VALUES(@UserId, @GameId)
F...
Linq to EntityFramework DateTime
...ntity Framework, your predicates inside the Where clause get translated to SQL. You're getting that error because there is no translation to SQL for DateTime.Add() which makes sense.
A quick work-around would be to read the results of the first Where statement into memory and then use LINQ to Objec...
Create a nonclustered non-unique index within the CREATE TABLE statement with SQL Server
It is possible to create a primary key or unique index within a SQL Server CREATE TABLE statement. Is it possible to create a non-unique index within a CREATE TABLE statement?
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ERROR: Error 1005: Can't create table (errno: 121)
I have troubles with forward engineering my MySQL database into WAMP server..
I was going to post an image of the schema but as this is my first post I can't.
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