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jQuery - Create hidden form element on the fly
What is the simplest way to dynamically create a hidden input form field using jQuery?
6 Answers
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NodeJS: How to get the server's port?
...uire('express')();
server.get('/', function(req, res) {
res.send("Hello Foo!");
});
var listener = server.listen(3000);
console.log('Your friendly Express server, listening on port %s', listener.address().port);
// Your friendly Express server, listening on port 3000
Again, this is tested in E...
Working with select using AngularJS's ng-options
...of the array item the option tag relates to. This is because AngularJS actually allows you to select entire objects with select controls, and not just primitive types. For example:
app.controller('MainCtrl', function($scope) {
$scope.items = [
{ id: 1, name: 'foo' },
{ id: 2, name: 'ba...
is node.js' console.log asynchronous?
...ete, since stdout is synchronous now.
Well let's see what console.log actually does.
First of all it's part of the console module:
exports.log = function() {
process.stdout.write(format.apply(this, arguments) + '\n');
};
So it simply does some formatting and writes to process.stdout, nothing ...
Can I “multiply” a string (in C#)?
...
I don't think it's elegant at all. In python the code to do this is: snip * multiplier (It's not horrible.. but neither is it beautiful).
– demented hedgehog
Jun 2 '15 at 2:56
...
Constructor function vs Factory functions
...function is used with the new keyword (which causes JavaScript to automatically create a new object, set this within the function to that object, and return the object):
var objFromConstructor = new ConstructorFunction();
A factory function is called like a "regular" function:
var objFromFactory...
How can I use Guzzle to send a POST request in JSON?
...se = $client->post('url', [
GuzzleHttp\RequestOptions::JSON => ['foo' => 'bar'] // or 'json' => [...]
]);
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Calling Java varargs method with single null argument?
If I have a vararg Java method foo(Object ...arg) and I call foo(null, null) , I have both arg[0] and arg[1] as null s. But if I call foo(null) , arg itself is null. Why is this happening?
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C++ deprecated conversion from string constant to 'char*'
...you are doing somewhere (not in the code you posted) something like:
void foo(char* str);
foo("hello");
The problem is that you are trying to convert a string literal (with type const char[]) to char*.
You can convert a const char[] to const char* because the array decays to the pointer, but wha...
Java's final vs. C++'s const
...on const instances. Java does not have an equivalent to this. E.g.:
class Foo {
public:
void bar();
void foo() const;
};
void test(const Foo& i) {
i.foo(); //fine
i.bar(); //error
}
Values can be assigned, once, later in Java only e.g.:
public class Foo {
void bar() {
...