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Getting raw SQL query string from PDO prepared statements
...O driver,
otherwise, it will be -1).
You can find more on the official php docs
Example:
<?php
/* Execute a prepared statement by binding PHP variables */
$calories = 150;
$colour = 'red';
$sth = $dbh->prepare('SELECT name, colour, calories
FROM fruit
WHERE calories < :calorie...
How to design RESTful search/filtering? [closed]
I'm currently designing and implementing a RESTful API in PHP. However, I have been unsuccessful implementing my initial design.
...
vs in Generics
...of the generic class, interface or method. The implication is that you can cast the type/interface/method to an equivalent with a super-type of T.
E.g. ICovariant<out Dog> can be cast to ICovariant<Animal>.
share...
How to convert JSON string to array
...
@RahulMehta If you're using PHP's built-in json_decode() it will return NULL if your JSON is invalid (for example, no quoted keys). That's what the documentation says and that's what my PHP 5.2 installation returns. Are you using a function other than...
Create JSON-object the correct way
I am trying to create an JSON object out of a PHP array. The array looks like this:
5 Answers
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jQuery loop over JSON result from AJAX Success?
...
You can also use the getJSON function:
$.getJSON('/your/script.php', function(data) {
$.each(data, function(index) {
alert(data[index].TEST1);
alert(data[index].TEST2);
});
});
This is really just a rewording of ifesdjeen's answer, but I thou...
JavaScript plus sign in front of function expression
...
Subsidiary to @TJCrowder's answer, + is usually used to force numerical casting of a value as this SO answer explains. In this instance it is called the 'unary plus operator' (for ease of googling).
var num = +variant;
So in front of a function it can be a way to force the function's result to...
How to pass parameters in GET requests with jQuery
...ng to handle error
}
});
And you can get the data by (if you are using PHP)
$_GET['ajaxid'] //gives 4
$_GET['UserID'] //gives you the sent userid
In aspx, I believe it is (might be wrong)
Request.QueryString["ajaxid"].ToString();
...
What is the “right” way to iterate through an array in Ruby?
PHP, for all its warts, is pretty good on this count. There's no difference between an array and a hash (maybe I'm naive, but this seems obviously right to me), and to iterate through either you just do
...
Adding two Java 8 streams, or an extra element to a stream
...type of Something<? extends T>, not the other way, so it couldn't be cast) Additional .map(identity()) cast <? extends T> to <T>. It happens thanks to mix of java 8 'target types' of method arguments and return types and signature of map() method. Actually it is Function.<T>i...