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How to send a JSON object using html form data

... Get complete form data as array and json stringify it. var formData = JSON.stringify($("#myForm").serializeArray()); You can use it later in ajax. Or if you are not using ajax; put it in hidden textarea and pass to server. If this data is passed as json stri...
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Find unused npm packages in package.json

Is there a way to determine if you have packages in your package.json file that are no longer needed? 6 Answers ...
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How do I add comments to package.json for npm install?

I've got a simple package.json file and I want to add a comment. Is there a way to do this, or are there any hacks to make this work? ...
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大数据时代的数据化运营 - 资讯 - 清泛网 - 专注C/C++及内核技术

...据量到一定程度的时候,我们才能分析出一些共性的东西区域性的东西。另外是数据的内存比较多,可能会衍生到很多纬度,比如身高长相,还有体重以及其他的年纪等等各种各样的东西,我们运营其实就是从大量的数据中挖...
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How to convert xml into array in php?

... = simplexml_load_string($xmlstring, "SimpleXMLElement", LIBXML_NOCDATA); $json = json_encode($xml); $array = json_decode($json,TRUE); share | improve this answer | follow ...
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parsing JSONP $http.jsonp() response in angular.js

I am using angular's $http.jsonp() request which is successfully returning json wrapped in a function: 8 Answers ...
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JSON.net: how to deserialize without using the default constructor?

... Json.Net prefers to use the default (parameterless) constructor on an object if there is one. If there are multiple constructors and you want Json.Net to use a non-default one, then you can add the [JsonConstructor] attribut...
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Add new attribute (element) to JSON object using JavaScript

How do I add new attribute (element) to JSON object using JavaScript? 10 Answers 10 ...
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How do I convert an object to an array?

...mensional arrays A somewhat dirty method is to use PHP >= 5.2's native JSON functions to encode to JSON and then decode back to an array. This will not include private and protected members, however, and is not suitable for objects that contain data that cannot be JSON encoded (such as binary d...
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RestSharp JSON Parameter Posting

... serialize the body yourself. Just do request.RequestFormat = DataFormat.Json; request.AddBody(new { A = "foo", B = "bar" }); // uses JsonSerializer If you just want POST params instead (which would still map to your model and is a lot more efficient since there's no serialization to JSON) do th...