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Correct way to load a Nib for a UIView subclass
...ndle] loadNibNamed:@"MyViewClassNib" owner:self options:nil] objectAtIndex:0]
I'm using this to initialise the reusable custom views I have.
Note that you can use "firstObject" at the end there, it's a little cleaner. "firstObject" is a handy method for NSArray and NSMutableArray.
Here's a typ...
How to format strings using printf() to get equal length in the output?
...
You can specify width on string fields, e.g.
printf("%-20s", "initialization...");
and then whatever's printed with that field will be blank-padded to the width you indicate.
The - left-justifies your text in that field.
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How to join two generators in Python?
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240
I think itertools.chain() should do it.
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psycopg2: insert multiple rows with one query
... located in another city.
I found out that using this method was about 10 times faster than executemany. In my case tup is a tuple containing about 2000 rows. It took about 10 seconds when using this method:
args_str = ','.join(cur.mogrify("(%s,%s,%s,%s,%s,%s,%s,%s,%s)", x) for x in tup)
cur.exe...
How to filter git diff based on file extensions?
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CB BaileyCB Bailey
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JavaScript module pattern with example [closed]
...larpattern = (function() {
// your module code goes here
var sum = 0 ;
return {
add:function() {
sum = sum + 1;
return sum;
},
reset:function() {
return sum = 0;
}
}
}());
alert(modularpattern.add()); //...
ArrayIndexOutOfBoundsException when using the ArrayList's iterator
....iterator().next() again and skipped entries.
– user500074
Jul 14 '11 at 22:34
@ larsmans Ah thank you very much. I to...
count vs length vs size in a collection
...ifferent from the length in cases like vectors (or strings), there may be 10 characters in a string, but storage is reserved for 20. It also may refer to number of elements - check source/documentation.
Capacity() - used to specifically refer to allocated space in collection and not number of valid...
Why can I access TypeScript private members when I shouldn't be able to?
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GuffaGuffa
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Replacing instances of a character in a string
...slicing to isolate the section of the string to replace in:
line = line[:10].replace(';', ':') + line[10:]
That'll replace all semi-colons in the first 10 characters of the string.
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