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How to sort two lists (which reference each other) in the exact same way
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13 Answers
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Extract first item of each sublist
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Using list comprehension:
>>> lst = [['a','b','c'], [1,2,3], ['x','y','z']]
>>> lst2 = [item[0] for item in lst]
>>> lst2
['a', 1, 'x']
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Python dictionary: Get list of values for list of keys
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213
A list comprehension seems to be a good way to do this:
>>> [mydict[x] for x in mykeys...
LISTAGG in Oracle to return distinct values
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edited Apr 13 '19 at 23:57
Jon Heller
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Difference between `set`, `setq`, and `setf` in Common Lisp?
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173
Originally, in Lisp, there were no lexical variables -- only dynamic ones. And
there was no SETQ...
How can I split a string into segments of n characters?
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369
var str = 'abcdefghijkl';
console.log(str.match(/.{1,3}/g));
Note: Use {1,3} inste...
How to make lists contain only distinct element in Python? [duplicate]
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Mark ByersMark Byers
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Formatting floats without trailing zeros
...rtelli
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6
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Remove all the elements that occur in one list from another
...e following statement does exactly what you want and stores the result in l3:
l3 = [x for x in l1 if x not in l2]
l3 will contain [1, 6].
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All but last element of Ruby array
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130
Perhaps...
a = t # => [1, 2, 3, 4]
a.first a.size - 1 # => [1, 2, 3]
or...