大约有 47,000 项符合查询结果（耗时：0.0489秒） [XML]
Generate colors between red and green for a power meter?
...
203
This should work - just linearly scale the red and green values. Assuming your max red/green/bl...
JS Client-Side Exif Orientation: Rotate and Mirror JPEG Images
...erver or anything.
– igneosaur
May 20 '16 at 8:28
3
@igneosaur: you can send base64 encoded data ...
Does ruby have real multithreading?
...
Updated with Jörg's Sept 2011 comment
You seem to be confusing two very different things here: the
Ruby Programming Language and the specific threading model of one
specific implementation of the Ruby Programming Language. There
are currently arou...
Difference between map, applymap and apply methods in Pandas
...
10 Answers
10
Active
...
What to use as an initial version? [closed]
I usually start my projects with a version 1.0.0. As soon as I have some stuff together, I release it as 1.0.0 and move on with 1.1.0.
...
Sorting arrays in NumPy by column
... copy:
In [1]: import numpy as np
In [2]: a = np.array([[1,2,3],[4,5,6],[0,0,1]])
In [3]: np.sort(a.view('i8,i8,i8'), order=['f1'], axis=0).view(np.int)
Out[3]:
array([[0, 0, 1],
[1, 2, 3],
[4, 5, 6]])
To sort it in-place:
In [6]: a.view('i8,i8,i8').sort(order=['f1'], axis=0) #&...
Floating point vs integer calculations on modern hardware
...|
edited Dec 19 '13 at 21:03
vy32
23.1k2828 gold badges9999 silver badges187187 bronze badges
answered M...
From inside of a Docker container, how do I connect to the localhost of the machine?
...
30 Answers
30
Active
...
Swift Beta performance: sorting arrays
...
tl;dr Swift 1.0 is now as fast as C by this benchmark using the default release optimisation level [-O].
Here is an in-place quicksort in Swift Beta:
func quicksort_swift(inout a:CInt[], start:Int, end:Int) {
if (end - start < 2...
What is the smallest possible valid PDF?
...ting problem. Taking it by the book, you can start off with this:
%PDF-1.0
1 0 obj<</Type/Catalog/Pages 2 0 R>>endobj 2 0 obj<</Type/Pages/Kids[3 0 R]/Count 1>>endobj 3 0 obj<</Type/Page/MediaBox[0 0 3 3]>>endobj
xref
0 4
0000000000 65535 f
0000000010 00000 n
00...