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Is there a 'box-shadow-color' property?
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answered Jun 10 '10 at 9:01
Andy EAndy E
300k7575 gold badges456456 silver badges436436 bronze badges
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How to hide one item in an Android Spinner
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50
To hide an arbitrary item or more than one item I think that you can implement your own adapter ...
UIView Infinite 360 degree rotation animation?
I'm trying to rotate a UIImageView 360 degrees, and have looked at several tutorials online. I could get none of them working, without the UIView either stopping, or jumping to a new position.
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Dictionary vs Object - which is more efficient and why?
...__init__(self, i):
self.i = i
self.l = []
all = {}
for i in range(1000000):
all[i] = Obj(i)
test_obj.py:
class Obj(object):
def __init__(self, i):
self.i = i
self.l = []
all = {}
for i in range(1000000):
all[i] = Obj(i)
test_dict.py:
all = {}
for i in range(1000000):
o = {}...
Replace multiple strings with multiple other strings
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– Michal Moravcik
Nov 21 '14 at 13:02
2
You may want to escape the keys for the regular expressi...
How to sort an array of associative arrays by value of a given key in PHP?
...'price'];
}
array_multisort($price, SORT_DESC, $inventory);
As of PHP 5.5.0 you can use array_column() instead of that foreach:
$price = array_column($inventory, 'price');
array_multisort($price, SORT_DESC, $inventory);
s...
Mac OSX Lion DNS lookup order [closed]
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10 Answers
10
Active
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Check whether an array is empty [duplicate]
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420
There are two elements in array and this definitely doesn't mean that array is empty. As a quick...
Flatten an Array of Arrays in Swift
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Swift >= 3.0
reduce:
let numbers = [[1,2,3],[4],[5,6,7,8,9]]
let reduced = numbers.reduce([], +)
flatMap:
let numbers = [[1,2,3],[4],[5,6,7,8,9]]
let flattened = numbers.flatMap { $0 }
joined:
let numbers = [[1,2,3],[4],[5,6,7,8...
Finding three elements in an array whose sum is closest to a given number
... >= j) {
// We got a match! All done.
if (A[i] + A[j] + A[k] == 0) return (A[i], A[j], A[k])
// We didn't match. Let's try to get a little closer:
// If the sum was too big, decrement k.
// If the sum was too small, increment j.
(A[i] + A[j] + A[k] > 0) ? k-- : j++...