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Regular expression to match numbers with or without commas and decimals in text

... 10 Answers 10 Active ...
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Python and pip, list all versions of a package that's available?

... 170 (update: As of March 2020, many people have reported that yolk, installed via pip install yolk3k...
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How to pretty-print a numpy.array without scientific notation and with given precision?

...o set the precision of the output: import numpy as np x=np.random.random(10) print(x) # [ 0.07837821 0.48002108 0.41274116 0.82993414 0.77610352 0.1023732 # 0.51303098 0.4617183 0.33487207 0.71162095] np.set_printoptions(precision=3) print(x) # [ 0.078 0.48 0.413 0.83 0.776 0.102...
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Find MongoDB records where array field is not empty

... the key, you can use: ME.find({ pictures: { $exists: true, $not: {$size: 0} } }) MongoDB don't use indexes if $size is involved, so here is a better solution: ME.find({ pictures: { $exists: true, $ne: [] } }) Since MongoDB 2.6 release, you can compare with the operator $gt but could lead to u...
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How to increase the gap between text and underlining in CSS

... 370 No, but you could go with something like border-bottom: 1px solid #000 and padding-bottom: 3px. ...
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Apply multiple functions to multiple groupby columns

...f = pd.DataFrame(np.random.rand(4,4), columns=list('abcd')) df['group'] = [0, 0, 1, 1] df a b c d group 0 0.418500 0.030955 0.874869 0.145641 0 1 0.446069 0.901153 0.095052 0.487040 0 2 0.843026 0.936169 0.926090 0.041722 1 3 0.635846 ...
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How to sort an array in descending order in Ruby

...Here's what I found out: #!/usr/bin/ruby require 'benchmark' ary = [] 1000.times { ary << {:bar => rand(1000)} } n = 500 Benchmark.bm(20) do |x| x.report("sort") { n.times { ary.sort{ |a,b| b[:bar] <=> a[:bar] } } } x.report("sort reverse") { n.times {...
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Get statistics for each group (such as count, mean, etc) using pandas GroupBy?

... counts – alvitawa Jun 24 '19 at 16:04 add a comment  |  ...
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Regular expression for matching HH:MM time format

... Your original regular expression has flaws: it wouldn't match 04:00 for example. This may work better: ^([0-1]?[0-9]|2[0-3]):[0-5][0-9]$ share | improve this answer | ...
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How to compare software version number using js? (only number)

...at if we have version strings that are not made up of just digits (e.g. "1.0a")? What should happen if one version string has more parts than the other? Most likely "1.0" should be considered less than "1.0.1", but what about "1.0.0"? Here's the code for an implementation that you can use directly...