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jQuery: what is the best way to restrict “number”-only input for textboxes? (allow decimal points)
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40 Answers
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How to check if element has any children in Javascript?
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or the length property of childNodes:
if (element.childNodes.length > 0) { // Or just `if (element.childNodes.length)`
// It has at least one
}
If you only want to know about child elements (as opposed to text nodes, attribute nodes, etc.) on all modern browsers (and IE8 — in fact, eve...
How to find indices of all occurrences of one string in another in JavaScript?
...tive) {
var searchStrLen = searchStr.length;
if (searchStrLen == 0) {
return [];
}
var startIndex = 0, index, indices = [];
if (!caseSensitive) {
str = str.toLowerCase();
searchStr = searchStr.toLowerCase();
}
while ((index = str.indexOf(...
Hibernate - Batch update returned unexpected row count from update: 0 actual row count: 0 expected:
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answered Apr 30 '10 at 9:55
beny23beny23
30.8k33 gold badges7575 silver badges8383 bronze badges
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get CSS rule's percentage value in jQuery
... built-in way, I'm afraid. You can do something like this:
var width = ( 100 * parseFloat($('.largeField').css('width')) / parseFloat($('.largeField').parent().css('width')) ) + '%';
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impro...
Understanding colors on Android (six characters)
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edited Nov 10 '14 at 10:54
answered Mar 26 '11 at 20:32
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CSS text-overflow in a table cell?
...flow to work. No extra layout div elements are required:
td
{
max-width: 100px;
overflow: hidden;
text-overflow: ellipsis;
white-space: nowrap;
}
For responsive layouts; use the max-width CSS property to specify the effective minimum width of the column, or just use max-width: 0; for unlimited ...
Detect rotation of Android phone in the browser with JavaScript
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Gajus
50.2k5353 gold badges220220 silver badges367367 bronze badges
answered Feb 21 '10 at 23:37
jb.jb.
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How can I check for an empty/undefined/null string in JavaScript?
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edited Jun 2 '18 at 0:29
user5779136
answered Sep 30 '08 at 17:20
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Swift how to sort array of custom objects by property value
...es : [imageFile] = []
Then you can simply do:
Swift 2
images.sorted({ $0.fileID > $1.fileID })
Swift 3+
images.sorted(by: { $0.fileID > $1.fileID })
The example above gives desc sort order
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