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Should I pass a shared_ptr by reference? [duplicate]
...ce, to avoid the overhead of copying the shared_ptr.
The best practice in C++ is always to have clearly defined ownership semantics for your objects. There is no universal "always do this" to replace actual thought.
If you always pass shared pointers by value, it gets costly (because they're a lot...
Copying a HashMap in Java
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The difference is that in C++ your object is on the stack, whereas in Java, your object is in the heap. If A and B are Objects, any time in Java you do:
B = A
A and B point to the same object, so anything you do to A you do to B and vice versa.
Us...
Pointer vs. Reference
...st practical difference for an output parameter is purely syntax. Google's C++ Style Guide (https://google.github.io/styleguide/cppguide.html#Reference_Arguments), for example, mandates only pointers for output parameters, and allows only references that are const. The reasoning is one of readabilit...
Questions every good Java/Java EE Developer should be able to answer? [closed]
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I confused a C++ lecturer yesterday with the diamond inheritance problem, she didn't know about it at all :)
– Esko
Jan 22 '10 at 10:01
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About “*.d.ts” in TypeScript
...as told by someone that this kind of file is something like "head file" in C++ but for JS only. But I cannot convert a pure JS file to *.d.ts file unless I forcely change the *.js to *.ts . So I have three files:
a JS file, a TS file and a *.d.ts file.
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Why does sizeof(x++) not increment x?
Here is the code compiled in dev c++ windows:
9 Answers
9
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How to call a parent class function from derived class function?
How do I call the parent function from a derived class using C++? For example, I have a class called parent , and a class called child which is derived from parent. Within
each class there is a print function. In the definition of the child's print function I would like to make a call to the ...
Recursive lambda functions in C++11
I am new to C++11. I am writing the following recursive lambda function, but it doesn't compile.
14 Answers
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Virtual member call in a constructor
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The rules of C# are very different from that of Java and C++.
When you are in the constructor for some object in C#, that object exists in a fully initialized (just not "constructed") form, as its fully derived type.
namespace Demo
{
class A
{
public A()
{
...
namespaces for enum types - best practices
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Original C++03 answer:
The benefit from a namespace (over a class) is that you can use using declarations when you want.
The problem with using a namespace is that namespaces can be expanded elsewhere in the code. In a large projec...