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How to add external library in IntelliJ IDEA?

... I've used this process to attach a 3rd party Jar to an Android project in IDEA. Copy the Jar to your libs/ directory Open Project Settings (Ctrl Alt Shift S) Under the Project Settings panel on the left, choose Modules On the larger right pane, choose the Dependencies tab Pre...
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【软著】软件著作权证书申请流程及注意事项,模板分享 - App Inventor 2 中...

...这些文件包含了组件行为、事件、方法等信息,用于在 Android 设备上执行应用。 生成 APK: 最后,App Inventor 会基于 .yail 文件和其他资源生成 .apk 文件,供用户下载并在 Android 设备上运行。 .yail 文件的作用: 中间表示: .ya...
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get the latest fragment in backstack

... RTFM: developer.android.com/reference/android/app/… – artkoenig Apr 5 '15 at 10:04 1 ...
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How to get Resource Name from Resource id

... No, u got it all wrong . I want to retrieve text radio1 from android:id="@+id/radio1" – Code_Life Apr 13 '12 at 8:50 ...
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Camera access through browser

... This is AWESOME on Android too! – Matt Oct 2 '13 at 3:30 1 ...
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What causes javac to issue the “uses unchecked or unsafe operations” warning

... For Android Studio, you need to add: allprojects { gradle.projectsEvaluated { tasks.withType(JavaCompile) { options.compilerArgs << "-Xlint:unchecked" } } // ... } in your projec...
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How can I get the current stack trace in Java?

... On android a far easier way is to use this: import android.util.Log; String stackTrace = Log.getStackTraceString(exception);
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How do I get the file name from a String containing the Absolute file path?

... How come it doesn't exist on Android? weird. – android developer Sep 9 '14 at 22:13 12 ...
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Convert JSON String to Pretty Print JSON output using Jackson

...pass the 4(indentSpaces) in toString() method. Note: It works fine in the android without any library. But in java you have to use the org.json library. share | improve this answer | ...
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How to go back to previous page if back button is pressed in WebView?

... If using Android 2.2 and above (which is most devices now), the following code will get you what you want. @Override public void onBackPressed() { if (webView.canGoBack()) { webView.goBack(); } else { super.on...