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How to sort with a lambda?
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edited Feb 25 '11 at 23:06
answered Feb 25 '11 at 22:51
B...
Finding the index of elements based on a condition using python list comprehension
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answered Sep 1 '11 at 13:20
Mike GrahamMike Graham
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Getting image dimensions without reading the entire file
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106
Your best bet as always is to find a well tested library. However, you said that is difficult, ...
Python - Create list with numbers between 2 values?
...s to be 16+1 = 17
EDIT:
To respond to the question about incrementing by 0.5, the easiest option would probably be to use numpy's arange() and .tolist():
>>> import numpy as np
>>> np.arange(11, 17, 0.5).tolist()
[11.0, 11.5, 12.0, 12.5, 13.0, 13.5,
14.0, 14.5, 15.0, 15.5, 16....
Is there a performance difference between i++ and ++i in C++?
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edited Mar 29 '18 at 20:08
zar
8,36377 gold badges6868 silver badges125125 bronze badges
answered Au...
Predicate in Java
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203
I'm assuming you're talking about com.google.common.base.Predicate<T> from Guava.
From t...
What's the meaning of * (asterisk) in XAML ColumnDefinition?
...s definition
<Grid.ColumnDefinitions>
<ColumnDefinition Width="0.07*"/>
<ColumnDefinition Width="0.93*"/>
</Grid.ColumnDefinitions>
The first column will get 7% of the total space available and the second column would get 93%. On the other hand if you had this definiti...
How to find the size of localStorage
...xecute this snippet in JavaScript console (one line version):
var _lsTotal=0,_xLen,_x;for(_x in localStorage){ if(!localStorage.hasOwnProperty(_x)){continue;} _xLen= ((localStorage[_x].length + _x.length)* 2);_lsTotal+=_xLen; console.log(_x.substr(0,50)+" = "+ (_xLen/1024).toFixed(2)+" KB")};console...
Why doesn't println! work in Rust unit tests?
...in.rs; ./main
running 1 test
test test ... ok
test result: ok. 1 passed; 0 failed; 0 ignored; 0 measured
% ./main --nocapture
running 1 test
Hidden output
test test ... ok
test result: ok. 1 passed; 0 failed; 0 ignored; 0 measured
% cargo test -- --nocapture
running 1 test
Hidden output
test ...
JavaScript - cannot set property of undefined
... data: c
};
};
If you're in an environment that supports ES2015 features, you can use computed property names:
d = {
[a]: {
greetings: b,
data: c
}
};
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