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How to convert local time string to UTC?

... Source code, using local timezone "America/Los_Angeles", for the string "2001-2-3 10:11:12": import pytz, datetime local = pytz.timezone ("America/Los_Angeles") naive = datetime.datetime.strptime ("2001-2-3 10:11:12", "%Y-%m-%d %H:%M:%S") local_dt = local.localize(naive, is_dst=None) utc_dt = loca...
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How does this JavaScript/jQuery syntax work: (function( window, undefined ) { })(window)?

... answered Apr 26 '10 at 19:19 VincentVincent 3,70622 gold badges1919 silver badges2828 bronze badges ...
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Increasing the maximum number of TCP/IP connections in Linux

... 401 Maximum number of connections are impacted by certain limits on both client & server sides,...
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C# elegant way to check if a property's property is null

... answered Nov 7 '14 at 2:03 Phillip NganPhillip Ngan 11.9k55 gold badges5555 silver badges7070 bronze badges ...
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30条爆笑的程序员梗 PHP是最好的语言 - 轻松一刻 - 清泛网 - 专注C/C++及内核技术

30条爆笑的程序员梗 PHP是最好的语言程序人员写程序,又将程序换酒钱;酒醒只在屏前坐,酒醉还来屏下眠;酒醉酒醒日复日,得自娱自乐才行。1.问答Q:你是怎么区分一个内向的程序员...程序人员写程序,又将程序换酒钱;酒醒只在屏...
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What is the most robust way to force a UIView to redraw?

...nd invoke it using -performSelector:withObject:afterDelay: with a delay of 0. That will put "some more logic" after the next draw cycle. See this question for an example of that kind of code, and a case where it might be needed (though it's usually best to look for other solutions if possible since ...
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How to have git log show filenames like svn log -v

... zb226 7,01144 gold badges3535 silver badges6262 bronze badges answered Aug 4 '09 at 21:48 CB BaileyCB Bailey ...
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How to print out more than 20 items (documents) in MongoDB's shell?

won't do it. It still prints out only 20 documents. 6 Answers 6 ...
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Set width of a “Position: fixed” div relative to parent div

I'm trying to give a div (position: fixed) the width of 100% (relating to it's parent div). But I've got some problems... 1...
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Check if an element contains a class in JavaScript?

...class1', 'class2', 'class3', 'class4']; test.innerHTML = ""; for(var i = 0, j = classes.length; i < j; i++) { if(hasClass(test, classes[i])) { test.innerHTML = "I have " + classes[i]; break; } } It's also less redundant ;) ...