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Vim: faster way to select blocks of text in visual mode
I have been using vim for quite some time and am aware that selecting blocks of text in visual mode is as simple as SHIFT + V and moving the arrow key up or down line-by-line until I reach the end of the block of text that I want selected.
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How to check if an option is selected?
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UPDATE
A more direct jQuery method to the option selected would be:
var selected_option = $('#mySelectBox option:selected');
Answering the question .is(':selected') is what you are looking for:
$('#mySelectBox option').each(function() {
if($(this).is(':selected')) ....
Check if a Windows service exists and delete in PowerShell
...ove-WmiObject -InputObject $s3
Remove-WmiObject : Access denied
At line:1 char:1
+ Remove-WmiObject -InputObject $s3
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo : InvalidOperation: (:) [Remove-WmiObject], ManagementException
+ FullyQualifiedErrorId : RemoveWMIManagementExcep...
set the width of select2 input (through Angular-ui directive)
I have problem making this plunkr (select2 + angulat-ui) work.
11 Answers
11
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What are the differences between Chosen and Select2?
Chosen and Select2 are the two more popular libraries for extending selectboxes.
11 Answers
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How do I style a dropdown with only CSS?
Is there a CSS-only way to style a <select> dropdown?
24 Answers
24
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What is the $? (dollar question mark) variable in shell scripting? [duplicate]
...able hold? I can't Google search the answer because they block punctuation characters.
9 Answers
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Delete all data in SQL Server database
...stem stored procs */
DECLARE @name VARCHAR(128)
DECLARE @SQL VARCHAR(254)
SELECT @name = (SELECT TOP 1 [name] FROM sysobjects WHERE [type] = 'P' AND category = 0 ORDER BY [name])
WHILE @name is not null
BEGIN
SELECT @SQL = 'DROP PROCEDURE [dbo].[' + RTRIM(@name) +']'
EXEC (@SQL)
PRINT ...
Select random row from a sqlite table
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Have a look at Selecting a Random Row from an SQLite Table
SELECT * FROM table ORDER BY RANDOM() LIMIT 1;
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Swift - encode URL
.../test"
let escapedString = originalString.addingPercentEncoding(withAllowedCharacters: .urlHostAllowed)
print(escapedString!)
Output:
test%2Ftest
Swift 1
In iOS 7 and above there is stringByAddingPercentEncodingWithAllowedCharacters
var originalString = "test/test"
var escapedString = orig...