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Programmer Puzzle: Encoding a chess board state throughout a game
... possible (but incredibly unlikely) for one side to end up with 9 queens, 10 rooks, 10 bishops or 10 knights if all 8 pawns get promoted.
Stalemate
When in a position from which you cannot win your best tactic is to try for a stalemate. The most likely variant is where you cannot make a legal move...
How to find the foreach index?
...
Giacomo1968
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answered Sep 26 '08 at 18:24
OwenOwen
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Determine device (iPhone, iPod Touch) with iOS
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answered Jan 15 '09 at 19:54
Adam RosenfieldAdam Rosenfield
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How to Execute SQL Server Stored Procedure in SQL Developer?
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TemaTema
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ld cannot find an existing library
... |
edited Nov 8 '12 at 21:05
Yamaneko
2,82722 gold badges2929 silver badges5252 bronze badges
answered D...
Android - Set max length of logcat messages
...size buffer in logcat for binary logs (/dev/log/events) and this limit is 1024 bytes.
For the non-binary logs there is also a limit:
#define LOGGER_ENTRY_MAX_LEN (4*1024)
#define LOGGER_ENTRY_MAX_PAYLOAD (LOGGER_ENTRY_MAX_LEN - sizeof(struct logger_entry))
So the real message size for bot...
Calling Java varargs method with single null argument?
...method foo(Object ...arg) and I call foo(null, null) , I have both arg[0] and arg[1] as null s. But if I call foo(null) , arg itself is null. Why is this happening?
...
CS0120: An object reference is required for the nonstatic field, method, or property 'foo'
...ling method:
private static void SumData(object state)
{
int result = 0;
//int[] icount = (int[])state;
int icount = (int)state;
for (int i = icount; i > 0; i--)
{
result += i;
System.Threading.Thread.Sleep(1000);
}
Form1 frm1 = new Form1();
frm1....
Recent file history in Vim?
... previous ten files into ~/.viminfo in the filemarks section. You can use '0, '1, '2, ... '9 to jump among them.
(Probably only useful for '0 to get back to the last file you were editing, unless your memory is stronger than mine.)
You can also use the :browse oldfiles command to get a menu with...
numpy: most efficient frequency counts for unique values in an array
...x = np.array([1,1,1,2,2,2,5,25,1,1])
y = np.bincount(x)
ii = np.nonzero(y)[0]
And then:
zip(ii,y[ii])
# [(1, 5), (2, 3), (5, 1), (25, 1)]
or:
np.vstack((ii,y[ii])).T
# array([[ 1, 5],
[ 2, 3],
[ 5, 1],
[25, 1]])
or however you want to combine the counts and th...
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