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How can I tell how many objects I've stored in an S3 bucket?

...ches of 1000 (which can be slow and suck bandwidth - amazon seems to never compress the XML responses), or log into your account on S3, and go Account - Usage. It seems the billing dept knows exactly how many objects you have stored! Simply downloading the list of all your objects will actually ta...
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Multiple RunWith Statements in jUnit

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Passing variables to the next middleware using next() in Express.js

...omevariable = variable1; As others have pointed out, res.locals is the recommended way of passing data through middleware. share | improve this answer | follow ...
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How can I clear previous output in Terminal in Mac OS X?

I know the clear command that 'clears' the current screen, but it does this just by printing lots of newlines - the cleared contents just get scrolled up. ...
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Eclipse “Error: Could not find or load main class”

...ave a project in eclipse on my laptop that I pushed to Git https://github.com/chrisbramm/LastFM-History-Graph.git 50 Answe...
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Numpy argsort - what is it doing?

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Drop all tables whose names begin with a certain string

...is did not work for me. The answer to this question worked: stackoverflow.com/questions/5116296/… – Ayushmati May 11 at 19:18 add a comment  |  ...
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Android: Clear Activity Stack

I'm having several activities in my application. and flow is very complicated. When I click the Logout application navigates to login Screen and from there user can exit by cancel button (calling system.exit(0) ) ...
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How do I get indices of N maximum values in a NumPy array?

... The simplest I've been able to come up with is: In [1]: import numpy as np In [2]: arr = np.array([1, 3, 2, 4, 5]) In [3]: arr.argsort()[-3:][::-1] Out[3]: array([4, 3, 1]) This involves a complete sort of the array. I wonder if numpy provides a built...
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How do you count the number of occurrences of a certain substring in a SQL varchar?

...t has values formatted like a,b,c,d. Is there a way to count the number of commas in that value in T-SQL? 20 Answers ...