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jQuery Validate - require at least one field in a group to be filled
...han's code without any changes
}, jQuery.format("Please fill out at least {0} of these fields."));
// "filone" is the class we will use for the input elements at this example
jQuery.validator.addClassRules("fillone", {
require_from_group: [1,".fillone"]
});
Code inside the html file:
<inp...
Better way to set distance between flexbox items
To set the minimal distance between flexbox items I'm using margin: 0 5px on .item and margin: 0 -5px on container. For me it seems like a hack, but I can't find any better way to do this.
...
iOS application: how to clear notifications?
...purposed [[UIApplication sharedApplication] setApplicationIconBadgeNumber: 0]; to clear said notifications. It might seem a bit weird, and Apple might provide a more intuitive way to do this in the future, but for the time being it's the official way.
Myself, I use this snippet:
[[UIApplication sh...
How to get a complete list of ticker symbols from Yahoo Finance? [closed]
...;IDSearchResult> resp3 = dl2.Download(index);
int i = 0;
foreach (var item in resp3.Result.Items)
{
writeStream.WriteLine(item.ID + "|" + item.ISIN + "|" + item.Name + "|" + item.Exchange + "|" + item.Type + "|" + item.Industry...
How to get item's position in a list?
... 3, 1, 2, 1, 6]
>>> [i for i,x in enumerate(testlist) if x == 1]
[0, 5, 7]
Update:
Okay, you want a generator expression, we'll have a generator expression. Here's the list comprehension again, in a for loop:
>>> for i in [i for i,x in enumerate(testlist) if x == 1]:
... p...
How can I make a TextArea 100% width without overflowing when padding is present in CSS?
...
answered Nov 11 '10 at 15:58
Piet BijlPiet Bijl
6,99422 gold badges1313 silver badges1010 bronze badges
...
How to crop an image using C#?
...aphics g = Graphics.FromImage(target))
{
g.DrawImage(src, new Rectangle(0, 0, target.Width, target.Height),
cropRect,
GraphicsUnit.Pixel);
}
share
...
Open Cygwin at a specific folder
...
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edited Jul 30 '18 at 8:51
Toolkit
8,67066 gold badges4848 silver badges5656 bronze badges
...
Check if a given key already exists in a dictionary
... intended way to test for the existence of a key in a dict.
d = {"key1": 10, "key2": 23}
if "key1" in d:
print("this will execute")
if "nonexistent key" in d:
print("this will not")
If you wanted a default, you can always use dict.get():
d = dict()
for i in range(100):
key = i % 1...