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Ruby replace string with captured regex pattern
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Note that this only works if the replacement string is inside single quotes. I wasted 5 minutes figuring that out.
– Vicky Chijwani
Feb 9 '13 at 0:30
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Troubleshooting “Illegal mix of collations” error in mysql
... two strings of incompatible collation or by attempting to select data of different collation into a combined column.
The clause COLLATE allows you to specify the collation used in the query.
For example, the following WHERE clause will always give the error you posted:
WHERE 'A' COLLATE latin1_g...
Renaming a virtualenv folder without breaking it
...table option. From the docs:
Normally environments are tied to a
specific path. That means that you
cannot move an environment around or
copy it to another computer. You can
fix up an environment to make it
relocatable with the command:
$ virtualenv --relocatable ENV
NOTE: EN...
Why do we usually use || over |? What is the difference?
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If you use the || and && forms, rather than the | and & forms of these operators, Java will not bother to evaluate the right-hand operand alone.
It's a matter of if you want to short-circuit the evaluation or not...
How to tell if node.js is installed or not
...ind further instructions. What does one really need to do? I wanted to see if it was actually working. So I executed a script called hello.js. It went as such:
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Difference between \A \z and ^ $ in Ruby regular expressions
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If you're depending on the regular expression for validation, you always want to use \A and \z. ^ and $ will only match up until a newline character, which means they could use an email like me@example.com\n<script>dang...
How to find common elements from multiple vectors?
...ect(a,b),c)
will do the job.
EDIT: More cleverly, and more conveniently if you have a lot of arguments:
Reduce(intersect, list(a,b,c))
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How to convert list to string [duplicate]
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By using ''.join
list1 = ['1', '2', '3']
str1 = ''.join(list1)
Or if the list is of integers, convert the elements before joining them.
list1 = [1, 2, 3]
str1 = ''.join(str(e) for e in list1)
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Negative list index? [duplicate]
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However, there is a caveat: the behavior is slightly different if you try slice notation. If you use -1 in that case, it returns one element from the last. >>> a = [1,2,3,4,5] >>> a[-1] 5 >>> a[:-1] [1, 2, 3, 4]
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How do I update a Python package?
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You might want to look into a Python package manager like pip. If you don't want to use a Python package manager, you should be able to download M2Crypto and build/compile/install over the old installation.
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