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How to validate an email address in PHP

...\\x23-\\x5B\\x5D-\\x7F]|(?:\\x5C[\\x00-\\x7F]))*\\x22)))*@(?:(?:(?!.*[^.]{64,})(?:(?:(?:xn--)?[a-z0-9]+(?:-+[a-z0-9]+)*\\.){1,126}){1,}(?:(?:[a-z][a-z0-9]*)|(?:(?:xn--)[a-z0-9]+))(?:-+[a-z0-9]+)*)|(?:\\[(?:(?:IPv6:(?:(?:[a-f0-9]{1,4}(?::[a-f0-9]{1,4}){7})|(?:(?!(?:.*[a-f0-9][:\\]]){7,})(?:[a-f0-9]{1...
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Regex Last occurrence?

... answered Dec 4 '11 at 11:30 stemastema 75.9k1616 gold badges8686 silver badges116116 bronze badges ...
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Xcode 4 - “Valid signing identity not found” error on provisioning profiles on a new Macintosh insta

I had a Macintosh I used to develop iPhone apps with using XCode 4. I now have a new Macintosh with a new install of... everything. ...
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Get the week start date and week end date from week number

... answered Aug 12 '09 at 16:14 Robin DayRobin Day 92.5k2222 gold badges110110 silver badges160160 bronze badges ...
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Regular expression to match standard 10 digit phone number

... ^(\+\d{1,2}\s)?\(?\d{3}\)?[\s.-]\d{3}[\s.-]\d{4}$ Matches the following 123-456-7890 (123) 456-7890 123 456 7890 123.456.7890 +91 (123) 456-7890 If you do not want a match on non-US numbers use ^(\+0?1\s)?\(?\d{3}\)?[\s.-]\d{3}[\s.-]\d{4}$ Update : As noticed by ...
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How do you round UP a number in Python?

... 24 Answers 24 Active ...
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Open Source Java Profilers [closed]

... herrtim 2,42911 gold badge2020 silver badges3232 bronze badges answered Jun 4 '09 at 4:16 ChiChi ...
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Find intersection of two nested lists?

... If you want: c1 = [1, 6, 7, 10, 13, 28, 32, 41, 58, 63] c2 = [[13, 17, 18, 21, 32], [7, 11, 13, 14, 28], [1, 5, 6, 8, 15, 16]] c3 = [[13, 32], [7, 13, 28], [1,6]] Then here is your solution for Python 2: c3 = [filter(lambda x: x in c1, sublist) for sublist in c2] ...
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Understanding how recursive functions work

... | edited Sep 5 '14 at 0:49 answered Sep 5 '14 at 0:43 ...
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Array slices in C#

...clude the Linq namespace with using System.Linq;): byte[] foo = new byte[4096]; var bar = foo.Take(41); If you really need an array from any IEnumerable<byte> value, you could use the ToArray() method for that. That does not seem to be the case here. ...