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Convert a list to a dictionary in Python
...p to a dictionary. Each even element represents the key to the dictionary, and the following odd element is the value
12 An...
When to throw an exception?
...e 1: say I have a function which is supposed to examine an arbitrary class and return true if that class inherits from List<>. This function asks the question, "Is this object a descendant of List?" This function should never throw an exception, because there are no gray areas in its operation...
Combining multiple git repositories
...-)
$ cp -r phd phd-backup
Move the content of phd/code to phd/code/code, and fix the history so that it looks like it has always been there (this uses git's filter-branch command):
$ cd phd/code
$ git filter-branch --index-filter \
'git ls-files -s | sed "s#\t#&code/#" |
GIT_INDEX_FI...
Is it possible to figure out the parameter type and return type of a lambda?
Given a lambda, is it possible to figure out it's parameter type and return type? If yes, how?
4 Answers
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How to get rspec-2 to give the full trace associated with a test failure?
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and fwiw if you use rspec with spork and guard you can create a .rspec file and add -b to it to get the output when you run your test suite
– shicholas
Mar 5 '13 at 21:20
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How to install and run phpize
... yum install php-devel on rhel/centos
– andrej
Nov 21 '13 at 11:23
4
How can this be...
Nested classes' scope?
I'm trying to understand scope in nested classes in Python. Here is my example code:
6 Answers
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What is the meaning of erb?
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erb stands for "Embedded RuBy". A .html.erb or .erb.html file is HTML with Ruby code embedded in; Rails will evaluate the Ruby to add content to the file dynamically, and will output a "pure" HTML file for rendering.
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Why does comparing strings using either '==' or 'is' sometimes produce a different result?
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@AlexanderSupertramp, because of string interning.
– Chris Rico
Feb 1 '15 at 9:34
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Single Line Nested For Loops
..., (2, 4), (3, 1), (3, 4)]
It's exactly the same as this nested for loop (and, as the tutorial says, note how the order of for and if are the same).
>>> combs = []
>>> for x in [1,2,3]:
... for y in [3,1,4]:
... if x != y:
... combs.append((x, y))
...
>...