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Getting raw SQL query string from PDO prepared statements
...O driver,
otherwise, it will be -1).
You can find more on the official php docs
Example:
<?php
/* Execute a prepared statement by binding PHP variables */
$calories = 150;
$colour = 'red';
$sth = $dbh->prepare('SELECT name, colour, calories
FROM fruit
WHERE calories < :calorie...
How to design RESTful search/filtering? [closed]
I'm currently designing and implementing a RESTful API in PHP. However, I have been unsuccessful implementing my initial design.
...
Code Golf: Collatz Conjecture
...ut by passing a number to it on the command line:
;
; >> $ ./collatz 123
; >> 123 --> 370 --> 185 --> 556 --> 278 --> 139 --> 418 --> 209 --> 628 --> 314
; >> --> 157 --> 472 --> 236 --> 118 --> 59 --> 178 --> 89 --> 268 --> 134...
Convert Rows to columns using 'Pivot' in SQL Server
..., 212),
(105, 2, 78),
(109, 2, 97),
(105, 3, 60),
(102, 3, 123),
(101, 3, 220),
(109, 3, 87);
If your values are known, then you will hard-code the query:
select *
from
(
select store, week, xCount
from yt
) src
pivot
(
sum(xcount)
for week in ([1], [2], [3])
) pi...
How to convert JSON string to array
...
@RahulMehta If you're using PHP's built-in json_decode() it will return NULL if your JSON is invalid (for example, no quoted keys). That's what the documentation says and that's what my PHP 5.2 installation returns. Are you using a function other than...
jQuery loop over JSON result from AJAX Success?
...
You can also use the getJSON function:
$.getJSON('/your/script.php', function(data) {
$.each(data, function(index) {
alert(data[index].TEST1);
alert(data[index].TEST2);
});
});
This is really just a rewording of ifesdjeen's answer, but I thou...
Do I have to guard against SQL injection if I used a dropdown?
... {
// Not Expected
}
Then use mysqli_* if you are using a version of php >= 5.3.0 which you should be, to save your result. If used correctly this will help with sql injection.
share
|
impr...
How to pass parameters in GET requests with jQuery
...ng to handle error
}
});
And you can get the data by (if you are using PHP)
$_GET['ajaxid'] //gives 4
$_GET['UserID'] //gives you the sent userid
In aspx, I believe it is (might be wrong)
Request.QueryString["ajaxid"].ToString();
...
Create JSON-object the correct way
I am trying to create an JSON object out of a PHP array. The array looks like this:
5 Answers
...
How to use hex color values
...
How would you handle 123ABC? The compiler is burking at it not being a digit.
– Islam Q.
Mar 2 '16 at 6:28
1
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