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How do I unload (reload) a Python module?

...t has already been imported by using the reload builtin function (Python 3.4+ only): from importlib import reload import foo while True: # Do some things. if is_changed(foo): foo = reload(foo) In Python 3, reload was moved to the imp module. In 3.4, imp was deprecated in favor ...
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Benchmarking small code samples in C#, can this implementation be improved?

...d. – Mike Dunlavey Jun 26 '09 at 12:49 2 I just updated to use Stopwatch.StartNew. Not a function...
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How to check for an undefined or null variable in JavaScript?

... 24 Answers 24 Active ...
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Bypass popup blocker on window.open when JQuery event.preventDefault() is set

... 144 Popup blockers will typically only allow window.open if used during the processing of a user ev...
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How slow are .NET exceptions?

... 4 Yes, people should certainly be aware that there's a performance cost associated with using exceptions inappropriately. I just think it's a ...
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How do I start a process from C#?

... | edited Jul 1 '14 at 17:57 monzie 62511 gold badge66 silver badges1212 bronze badges answered ...
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Regex to test if string begins with http:// or https://

... JakeTheSnake 2,32433 gold badges1111 silver badges2222 bronze badges answered Jan 10 '11 at 2:03 cdhowiecdhowie ...
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CSS force image resize and keep aspect ratio

...px; width: auto; height: auto; } <p>This image is originally 400x400 pixels, but should get resized by the CSS:</p> <img width="400" height="400" src="http://i.stack.imgur.com/aEEkn.png"> This will make image shrink if it's too big for specified area (as downside, i...
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What is memory fragmentation?

... Steve JessopSteve Jessop 251k3131 gold badges420420 silver badges659659 bronze badges 1 ...
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In Python, what is the difference between “.append()” and “+= []”?

...ormance: append is twice as fast. Python 3.0 (r30:67507, Dec 3 2008, 20:14:27) [MSC v.1500 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> import timeit >>> timeit.Timer('s.append("something")', 's = []').timeit() 0.201774244999...