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How to create json by JavaScript for loop?
...ID"); // this works too
var status = document.getElementsByName("status")[0];
var jsonArr = [];
for (var i = 0; i < status.options.length; i++) {
jsonArr.push({
id: status.options[i].text,
optionValue: status.options[i].value
});
}
</script>
...
convert '1' to '0001' in JavaScript [duplicate]
How can I convert convert '1' to '0001' in JavaScript without using any 3rd party libraries. I have done this in php using spritf: $time = sprintf('%04.0f',$time_arr[$i]);
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Can someone give an example of cosine similarity, in a very simple, graphical way?
...
10 Answers
10
Active
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Using jQuery to see if a div has a child with a certain class
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201
You can use the find function:
if($('#popup').find('p.filled-text').length !== 0)
// Do Stu...
How do I format a long integer as a string without separator in Java?
... |
edited Jan 22 '16 at 20:19
RAnders00
4,20144 gold badges2929 silver badges5757 bronze badges
answere...
Should private helper methods be static if they can be static
... blong
2,65566 gold badges3232 silver badges9090 bronze badges
answered Feb 11 '09 at 21:33
Esko LuontolaEsko Luontola
70.3...
Python list iterator behavior and next(iterator)
...tion to i being printed each iteration:
>>> a = iter(list(range(10)))
>>> for i in a:
... print(i)
... next(a)
...
0
1
2
3
4
5
6
7
8
9
So 0 is the output of print(i), 1 the return value from next(), echoed by the interactive interpreter, etc. There are just 5 iterations, ...
How do I use itertools.groupby()?
... ("vehicle", "school bus")]
for key, group in groupby(things, lambda x: x[0]):
for thing in group:
print("A %s is a %s." % (thing[1], key))
print("")
This will give you the output:
A bear is a animal.
A duck is a animal.
A cactus is a plant.
A speed boat is a vehicle.
A schoo...
How to implement has_many :through relationships with Mongoid and mongodb?
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edited Aug 13 '11 at 20:31
answered Aug 13 '11 at 20:06
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What is a method that can be used to increment letters?
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180
Simple, direct solution
function nextChar(c) {
return String.fromCharCode(c.charCodeAt(0) +...