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json_encode sparse PHP array as JSON array, not JSON object

I have the following array in PHP: 4 Answers 4 ...
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PHP mkdir: Permission denied problem

I am trying to create a directory with PHP mkdir function but I get an error as follows: Warning: mkdir() [function.mkdir]: Permission denied in ... . How to settle down the problem? ...
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What does -> mean in Python function definitions?

...versions. According to this, the example you've supplied: def f(x) -> 123: return x will be forbidden in the future (and in current versions will be confusing), it would need to be changed to: def f(x) -> int: return x for it to effectively describe that function f returns an ob...
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LINUX下用PHPIZE安装PHP GD扩展 - 更多技术 - 清泛网 - 专注C/C++及内核技术

LINUX下用PHPIZE安装PHP GD扩展环境:LNMP in centOS 6.4。linux下PHP的扩展可以用phpize的方法,比较简单地进行启用。以下以PHP-GD2 库安装为例子。sudoyuminstallph...环境:LNMP in centOS 6.4。 linux下PHP的扩展可以用phpize的方法,比较简单地进行...
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Are “elseif” and “else if” completely synonymous?

... From the PHP manual: In PHP, you can also write 'else if' (in two words) and the behavior would be identical to the one of 'elseif' (in a single word). The syntactic meaning is slightly different (if you're familiar with C, this i...
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Traits vs. interfaces

I've been trying to study up on PHP lately, and I find myself getting hung up on traits. I understand the concept of horizontal code reuse and not wanting to necessarily inherit from an abstract class. What I don't understand is: What is the crucial difference between using traits versus interfaces?...
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Parsing domain from a URL

... Or simply: print parse_url($url, PHP_URL_HOST)) if you don't need the $parse array for anything else. – rybo111 Aug 24 '16 at 12:03 ...
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How to add a new method to a php object on the fly?

...ure, I'm not saying I'm an expert at extending an object during runtime in PHP, but I honestly can't say I see much wrong with it. (maybe I just have poor taste) – karim79 May 30 '10 at 9:13 ...
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How to remove duplicate values from an array in PHP

How can I remove duplicate values from an array in PHP? 24 Answers 24 ...
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JSON encode MySQL results

... $rows[] = $r; } print json_encode($rows); The function json_encode needs PHP >= 5.2 and the php-json package - as mentioned here NOTE: mysql is deprecated as of PHP 5.5.0, use mysqli extension instead http://php.net/manual/en/migration55.deprecated.php. ...