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How can I get all the request headers in Django?
I need to get all the Django request headers. From what i've read, Django simply dumps everything into the request.META variable along with a lot aof other data. What would be the best way to get all the headers that the client sent to my Django application?
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Difference between Mock / Stub / Spy in Spock test framework
... replacing a real one, returning something like null or 0 for each method call. You use a mock if you need a dummy instance of a complex class which would otherwise use external resources like network connections, files or databases or maybe use dozens of other objects. The advantage of mocks is tha...
How do I clear only a few specific objects from the workspace?
I would like to remove some data from the workspace. I know the "Clear All" button will remove all data. However, I would like to remove just certain data.
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How can I show dots (“…”) in a span with hidden overflow?
... standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book</span>
JSFiddle
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How do you trigger a block after a delay, like -performSelector:withObject:afterDelay:?
Is there a way to call a block with a primitive parameter after a delay, like using performSelector:withObject:afterDelay: but with an argument like int / double / float ?
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DataContractSerializer doesn't call my constructor?
...sible : when deserializing an object, the DataContractSerializer doesn't call the constructor !
4 Answers
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Filter by property
...to Python to evaluate the property--and at that point, you've already done all the work to load it.
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Looping over arrays, printing both index and value
...., not splitting them on whitespace. If foo=(x 'y z'), then f "${foo[@]}" calls f with two arguments, x and 'y z'. Metadata queries like "${!foo[@]}" and "${#foo[@]}" similarly act on foo as an array.
– BallpointBen
Sep 5 '18 at 1:23
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Divide a number by 3 without using *, /, +, -, % operators
...n which performs the desired operation. But it requires the + operator, so all you have left to do is to add the values with bit-operators:
// replaces the + operator
int add(int x, int y)
{
while (x) {
int t = (x & y) << 1;
y ^= x;
x = t;
}
return y;
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What's the purpose of using braces (i.e. {}) for a single-line if or loop?
...le is editor-agnostic beyond what you need, but not beyond what people actually use to edit C++. Hence "defensive".
– Steve Jessop
Aug 30 '12 at 10:11
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