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How do I handle too long index names in a Ruby on Rails ActiveRecord migration?
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Should also have foreign_key: true and by the way, this is a great solution since it's the easiest to use when you have a migration file created with the rails generator model:references format
– Abram
Feb 14 '17 at 2:29
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Sorting an IList in C#
...Engine property, I believe you could sort as follows:
from c in list
orderby c.Engine
select c;
Edit: You do need to be quick to get answers in here. As I presented a slightly different syntax to the other answers, I will leave my answer - however, the other answers presented are equally valid.
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LINQ to Entities only supports casting EDM primitive or enumeration types with IEntity interface
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I was able to resolve this by adding the class generic type constraint to the extension method. I'm not sure why it works, though.
public static T GetById<T>(this IQueryable<T> collection, Guid id)
where T : class, IEntity
{
//...
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Are there conventions on how to name resources?
...ique ones (sometimes gets reused) get prefixed with generic ones separated by an underscore.
The underscore is one thing, I observed, for example:
Layout width is layout_width in xml and layoutWidth in code, so I try to stick to it as list_apple
So a Login button will be login, but if we have ...
How do I remove the passphrase for the SSH key without having to create a new key?
...e. The latest versions of gpg-agent also support the protocol that is used by ssh-agent.
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How do I (or can I) SELECT DISTINCT on multiple columns?
...INCT a,b,c FROM t
is roughly equivalent to:
SELECT a,b,c FROM t GROUP BY a,b,c
It's a good idea to get used to the GROUP BY syntax, as it's more powerful.
For your query, I'd do it like this:
UPDATE sales
SET status='ACTIVE'
WHERE id IN
(
SELECT id
FROM sales S
INNER JOIN
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Fastest way to count exact number of rows in a very large table?
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@zerkmsby: For COUNT(key) I meant COUNT(primarykey) which should be non nullable. I'll clarify
– gbn
May 20 '11 at 8:30
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How to generate random SHA1 hash to use as ID in node.js?
... the most insane parallel computing situations. I know its silly and randomBytes(20) is going to be unique, but its just a confidence we can have because we may not be familiar with internals of random generation of another library.
– Dmitri R117
Sep 5 '17 at 1...
MySQL join with where clause
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How to resume Fragment from BackStack if exists
...pop the back stack based on either the transaction name or the id provided by commit. Using the name may be easier since it shouldn't require keeping track of a number that may change and reinforces the "unique back stack entry" logic.
Since you want only one back stack entry per Fragment, make the...