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How do I check which version of NumPy I'm using?
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This is not the public API, numpy.__version__ is.
– David Cournapeau
Nov 22 '11 at 10:10
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Decode Base64 data in Java
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As of Java 8, there is an officially supported API for Base64 encoding and decoding.
In time this will probably become the default choice.
The API includes the class java.util.Base64 and its nested classes. It supports three different flavors: basic, URL safe, and MIME.
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Check image width and height before upload with Javascript
...fari unless you have safari 6.0. 6.0 is the only version that support file API as of now. And I don't think apple ever gonna release 6.0 for windows. 5.1.7 have been the latest verson of safari from soooo long ago
– Seho Lee
Nov 28 '12 at 11:59
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Converting between strings and ArrayBuffers
...for Safari Mobile(ios) at 2018-04-18: developer.mozilla.org/en-US/docs/Web/API/TextDecoder
– bronze man
Apr 18 '18 at 7:46
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Mapping composite keys using EF code first
...617(v=vs.113).aspx
2) How to add a composite unique key using EF 6 Fluent Api?
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Why shouldn't all functions be async by default?
...ally not good - it's hiding the fact that you're using CPU cycles under an API that appears to be asynchronous, but is really not necessarily truly asynchronous.
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What does the slash mean in help() output?
...eters. Before Python 3.8, such parameters could only be specified in the C API.
It means the key argument to __contains__ can only be passed in by position (range(5).__contains__(3)), not as a keyword argument (range(5).__contains__(key=3)), something you can do with positional arguments in pure-py...
how to get android screen size programmatically, once and for all?
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If you are using api level 17 or higher check out getRealMetrics and getRealSize in Display
For api level 14,15 & 16 look here
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JavaScript: Create and save file [duplicate]
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w3.org/TR/file-writer-api/#the-filesaver-interface says "Work on this document has been discontinued and it should not be referenced or used as a basis for implementation."
– Godsmith
Jun 8 '15 at 16:35
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Using Java to find substring of a bigger string using Regular Expression
...within the square brackets in the first group. Have a look at the Pattern API Documentation for more information.
To extract the string, you could use something like the following:
Matcher m = MY_PATTERN.matcher("FOO[BAR]");
while (m.find()) {
String s = m.group(1);
// s now contains "BAR...