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Ruby ampersand colon shortcut [duplicate]
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Your question is wrong, so to speak. What's happening here isn't "ampersand and colon", it's "ampersand and object". The colon in this case is for the symbol. So, there's & and there's :foo.
The & calls to_proc on the object, and passes it as a blo...
Eclipse keyboard shortcut to indent source code to the left?
I've looked in the keyboard shortcuts list in Eclipse but can't find keyboard shortcut to indent source code to the left. Surely there is one?
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Remove duplicate entries using a Bash script [duplicate]
I want to remove duplicate entries from a text file, e.g:
4 Answers
4
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How to assign colors to categorical variables in ggplot2 that have stable mapping?
I've been getting up to speed with R in the last month.
5 Answers
5
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What is the difference between sigaction and signal?
I was about to add an extra signal handler to an app we have here and I noticed that the author had used sigaction() to set up the other signal handlers. I was going to use signal() . To follow convention I should use sigaction() but if I was writing from scratch, which should I choose?
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Why em instead of px?
...should define sizes and distances in your stylesheet with em instead of in pixels. So the question is why should I use em instead of px when defining styles in css? Is there a good example that illustrates this?
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Instance variable: self vs @
...n the instance variable @age — but could do any number of other things depending on how the age method is implemented in a given subclass. For example, you might have a MiddleAgedSocialite class that always reports its age 10 years younger than it actually is. Or more practically, a PersistentPers...
Is it possible to for SQL Output clause to return a column not being inserted?
...igrate the old data to the new tables. For that, I need to fill a table (ReportOptions) taking the data from the original table (Practice), and fill a second intermediate table (PracticeReportOption).
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How do I find duplicates across multiple columns?
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Duplicated id for pairs name and city:
select s.id, t.*
from [stuff] s
join (
select name, city, count(*) as qty
from [stuff]
group by name, city
having count(*) > 1
) t on s.name = t.name and s.city = t.ci...
Get a substring of a char* [duplicate]
For example, I have this
5 Answers
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