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Name of this month (Date.today.month as name)
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answered Jan 30 '11 at 17:18
Dylan MarkowDylan Markow
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jQuery UI Sortable Position
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answered Jun 6 '10 at 13:31
Nick Craver♦Nick Craver
580k125125 gold badges12551255 silver badges11351135 bronze badges
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Large Numbers in Java
...a.math package.
Example:
BigInteger reallyBig = new BigInteger("1234567890123456890");
BigInteger notSoBig = new BigInteger("2743561234");
reallyBig = reallyBig.add(notSoBig);
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improve thi...
Replacement for “rename” in dplyr
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dplyr version 0.3 added a new rename() function that works just like plyr::rename().
df <- rename(df, new_name = old_name)
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i...
Script parameters in Bash
...n the variables $1 and $2 and $3 where the number refers to the argument. $0 is the command itself.
The arguments are seperated by spaces, so if you would provide the -from and -to in the command, they will end up in these variables too, so for this:
./ocrscript.sh -from /home/kristoffer/test.png ...
Remove 'a' from legend when using aesthetics and geom_text
... FALSE)
The argument show_guide changed name to show.legend in ggplot2 2.0.0 (see release news).
Pre-ggplot2 2.0.0:
With show_guide = FALSE like so...
ggplot( data=iris, aes(x=Sepal.Length, y=Sepal.Width , colour = Species , shape = Species, label = Species ) , size=20 ) +
geom_point()+
geom...
How to limit depth for recursive file list?
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509
Checkout the -maxdepth flag of find
find . -maxdepth 1 -type d -exec ls -ld "{}" \;
Here I u...
How to create json by JavaScript for loop?
...ID"); // this works too
var status = document.getElementsByName("status")[0];
var jsonArr = [];
for (var i = 0; i < status.options.length; i++) {
jsonArr.push({
id: status.options[i].text,
optionValue: status.options[i].value
});
}
</script>
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Format date to MM/dd/yyyy in JavaScript [duplicate]
I have a dateformat like this '2010-10-11T00:00:00+05:30' . I have to format in to MM/dd/yyyy using JavaScript or jQuery . Anyone help me to do the same.
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C# Double - ToString() formatting with two decimal places but no rounding
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210
I use the following:
double x = Math.Truncate(myDoubleValue * 100) / 100;
For instance:
If t...
