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In jQuery, how do I select an element by its name attribute?
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This should do it, all of this is in the documentation, which has a very similar example to this:
$("input[type='radio'][name='theme']").click(function() {
var value = $(this).val();
});
I should also note you have multiple identical IDs...
Npm Please try using this command again as root/administrator
I've been desperately trying to install modules using node.js but it always fails getting packages with npm.
32 Answers
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Lambda expression vs method reference [closed]
...ded this feature to the language, when clearly we didn't strictly need to (all methods refs can be expressed as lambdas.)
Note that there is no right answer. Anyone who says "always use a method ref instead of a lambda" or "always use a lambda instead of a method ref" should be ignored.
This qu...
How do I check if a Sql server string is null or empty
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@irfandar - Well, if you want to treat a string with all spaces as empty, go ahead use trim. Otherwise a string with all spaces is not empty.
– Martin Ba
Sep 2 '13 at 12:13
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Check if inputs are empty using jQuery
I have a form that I would like all fields to be filled in. If a field is clicked into and then not filled out, I would like to display a red background.
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127 Return code from $?
...ommand, because it doesn't know where to find the binary you're trying to call.
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BestPractice - Transform first character of a string into lower case
... However, + is much faster than string.Format. Use the latter when you actually need to format something (like displaying integers, doubles or dates).
– Dirk Vollmar
Aug 25 '10 at 11:09
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How can I get the iOS 7 default blue color programmatically?
... Yes, definitely not a good idea to hard-code any value that could potentially change. Especially when there is an API to query the actual value.
– Nicolas Miari
Oct 2 '15 at 2:49
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Set the selected index of a Dropdown using jQuery
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First of all - that selector is pretty slow. It will scan every DOM element looking for the ids. It will be less of a performance hit if you can assign a class to the element.
$(".myselect")
To answer your question though, there ...
jQuery $(“#radioButton”).change(…) not firing during de-selection
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Looks like the change() function is only called when you check a radio button, not when you uncheck it. The solution I used is to bind the change event to every radio button:
$("#r1, #r2, #r3").change(function () {
Or you could give all the radio buttons the same...