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How do you find out the type of an object (in Swift)?

When trying to understand a program, or in some corner-cases, it's useful to be able to actually find out what type something is. I know the debugger can show you some type information, and you can usually rely on type inference to get away with not specifying the type in those situations, but still...
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Is there any boolean type in Oracle databases?

Is there any Boolean type in Oracle databases, similar to the BIT datatype in Ms SQL Server? 11 Answers ...
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Is it good practice to make the constructor throw an exception? [duplicate]

Is it a good practice to make the constructor throw an exception? For example I have a class Person and I have age as its only attribute. Now I provide the class as ...
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How do I make a batch file terminate upon encountering an error?

... How do I make it terminate immediately if one of the calls returns an error code of any level? 9 Answers ...
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Split value from one field to two

... Unfortunately MySQL does not feature a split string function. However you can create a user defined function for this, such as the one described in the following article: MySQL Split String Function by Federico Cargnelutti W...
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What is the difference between loose coupling and tight coupling in the object oriented paradigm?

...e the exact difference between loose coupling and tight coupling in Object oriented paradigm? 16 Answers ...
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Create an empty object in JavaScript with {} or new Object()?

...ere is no benefit to using new Object(); - whereas {}; can make your code more compact, and more readable. For defining empty objects they're technically the same. The {} syntax is shorter, neater (less Java-ish), and allows you to instantly populate the object inline - like so: var myObject = { ...
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How to encrypt/decrypt data in php?

... made some online research and some of them were quite confusing(at least for me). 6 Answers ...
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How can I use map and receive an index as well in Scala?

... I believe you're looking for zipWithIndex? scala> val ls = List("Mary", "had", "a", "little", "lamb") scala> ls.zipWithIndex.foreach{ case (e, i) => println(i+" "+e) } 0 Mary 1 had 2 a 3 little 4 lamb From: http://www.artima.com/forums/fla...
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Convert string with commas to array

... For simple array members like that, you can use JSON.parse. var array = JSON.parse("[" + string + "]"); This gives you an Array of numbers. [0, 1] If you use .split(), you'll end up with an Array of strings. ["0", "1"...