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PDO get the last ID inserted

... | edited Feb 1 '17 at 8:06 Your Common Sense 149k2929 gold badges182182 silver badges298298 bronze badges ...
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How to change MySQL column definition?

...-definition e.g. ALTER TABLE test MODIFY COLUMN locationExpect VARCHAR(120); share | improve this answer | follow | ...
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Cause CMAKE to generate an error

... | edited Oct 5 '19 at 13:04 squareskittles 10.5k77 gold badges2727 silver badges4343 bronze badges answ...
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C++: variable 'std::ifstream ifs' has initializer but incomplete type

... 107 This seems to be answered - #include <fstream>. The message means :- incomplete type - ...
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MySQL Select minimum/maximum among two (or more) given values

... use LEAST and GREATEST function to achieve it. SELECT GREATEST(A.date0, B.date0) AS date0, LEAST(A.date1, B.date1) AS date1 FROM A, B WHERE B.x = A.x Both are described here http://dev.mysql.com/doc/refman/5.0/en/comparison-operators.html ...
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Using two values for one switch case statement

...tic void main(String[] args) { int month = 2; int year = 2000; int numDays = 0; switch (month) { case 1: case 3: case 5: case 7: case 8: case 10: case 12: numDays = 3...
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Reference: Comparing PHP's print and echo

...e should one wish to use print in a conditional expression. Why 1 and not 100? Well in PHP the truthiness of 1 or 100 is the same, i.e. true, whereas 0 in a boolean context equates as a false value. In PHP all non-zero values (positive and negative) are truthy values and this derives from PHP's Per...
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How to calculate the number of days between two dates? [duplicate]

... const oneDay = 24 * 60 * 60 * 1000; // hours*minutes*seconds*milliseconds const firstDate = new Date(2008, 1, 12); const secondDate = new Date(2008, 1, 22); const diffDays = Math.round(Math.abs((firstDate - secondDate) / oneDay)); ...
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How do I explicitly specify a Model's table-name mapping in Rails?

... ZabbaZabba 58.5k4040 gold badges169169 silver badges198198 bronze badges ...
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How to flatten only some dimensions of a numpy array

... Take a look at numpy.reshape . >>> arr = numpy.zeros((50,100,25)) >>> arr.shape # (50, 100, 25) >>> new_arr = arr.reshape(5000,25) >>> new_arr.shape # (5000, 25) # One shape dimension can be -1. # In this case, the value is inferred from # the le...