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javascript find and remove object in array based on key value
...ergiBergi
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12
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Configuration System Failed to Initialize
... or app.config if windows) in your project starts as:
<?xml version="1.0"?>
<configuration>
<configSections>
<sectionGroup name="applicationSettings"
type="System.Configuration.ApplicationSettingsGroup, System, Version=4.0.0.0, Culture=neutral...
Obtaining a powerset of a set in Java
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101
Yes, it is O(2^n) indeed, since you need to generate, well, 2^n possible combinations. Here's a...
css3 transition animation on load?
...enu sliding into place using CSS3 only:
@keyframes slideInFromLeft {
0% {
transform: translateX(-100%);
}
100% {
transform: translateX(0);
}
}
header {
/* This section calls the slideInFromLeft animation we defined above */
animation: 1s ease-out 0s 1 slideInFromLeft;
...
How to use JUnit and Hamcrest together?
...lems.
– Adrien Be
Sep 11 '12 at 11:40
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show 2 more comments
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ArrayIndexOutOfBoundsException with custom Android Adapter for multiple views in ListView
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edited May 26 '14 at 8:03
Vikalp Patel
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answer...
Should all jquery events be bound to $(document)?
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edited Oct 10 '12 at 17:28
answered Oct 10 '12 at 17:05
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How to delete a module in Android Studio
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607
The "Mark as Excluded" option isn't there anymore.
The current (Android Studio 0.8.x - 2.2.x) ...
Reverting a single file to a previous version in git [duplicate]
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910
Let's start with a qualitative description of what we want to do (much of this is said in Ben St...
Convert a list to a dictionary in Python
...), which would normally be a code smell.
b = {a[i]: a[i+1] for i in range(0, len(a), 2)}
So the iter()/izip() method is still probably the most Pythonic in Python 3, although as EOL notes in a comment, zip() is already lazy in Python 3 so you don't need izip().
i = iter(a)
b = dict(zip(i, i))
...