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Removing duplicates in lists
...t;> list(OrderedDict.fromkeys(t))
[1, 2, 3, 5, 6, 7, 8]
Starting with Python 3.7, the built-in dictionary is guaranteed to maintain the insertion order as well, so you can also use that directly if you are on Python 3.7 or later (or CPython 3.6):
>>> list(dict.fromkeys(t))
[1, 2, 3, 5...
Catching an exception while using a Python 'with' statement
To my shame, I can't figure out how to handle exception for python 'with' statement. If I have a code:
4 Answers
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How can I find all matches to a regular expression in Python?
In a program I'm writing I have Python use the re.search() function to find matches in a block of text and print the results. However, the program exits once it finds the first match in the block of text.
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Cleanest and most Pythonic way to get tomorrow's date?
What is the cleanest and most Pythonic way to get tomorrow's date? There must be a better way than to add one to the day, handle days at the end of the month, etc.
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How can I break up this long line in Python?
...be joined to a second.")
Explicit is better than implicit, as the zen of python says, but this creates three strings instead of one, and uses twice as much memory: there are the two you have written, plus one which is the two of them joined together, so you have to know when to ignore the zen. Th...
Counting the Number of keywords in a dictionary in python
...Some modifications were made on posted answer UnderWaterKremlin to make it python3 proof. A surprising result below as answer.
System specs:
python =3.7.4,
conda = 4.8.0
3.6Ghz, 8 core, 16gb.
import timeit
d = {x: x**2 for x in range(1000)}
#print (d)
print (len(d))
# 1000
print (len(d.keys()...
Items in JSON object are out of order using “json.dumps”?
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Both Python dict (before Python 3.7) and JSON object are unordered collections. You could pass sort_keys parameter, to sort the keys:
>>> import json
>>> json.dumps({'a': 1, 'b': 2})
'{"b": 2, "a": 1}'
>>&...
List of zeros in python [duplicate]
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$python 2.7.8
from timeit import timeit
import numpy
timeit("list(0 for i in xrange(0, 100000))", number=1000)
> 8.173301935195923
timeit("[0 for i in xrange(0, 100000)]", number=1000)
> 4.881675958633423
timeit("[0]...
Pythonic way of checking if a condition holds for any element of a list
I have a list in Python, and I want to check if any elements are negative. Specman has the has() method for lists which does:
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Python memoising/deferred lookup property decorator
...posed in other answers since (ref 1and 2). Seems this is a popular one in Python web frameworks (derivatives exist in Pyramid and Werkzeug).
– André Caron
Dec 5 '13 at 11:20
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