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Is there a way to pass the DB user password into the co<em>mem><em>mem>and line tool <em>mem>ysqlad<em>mem>in?

I currently use the following but it ALWAYS pro<em>mem>pts <em>mem>e to <em>mem>anually type the password. Is there any way to pass it in on the co<em>mem><em>mem>and line when launching the executable? ...
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correct way to use super (argu<em>mem>ent passing)

So I was following Python's Super Considered Har<em>mem>ful , and went to test out his exa<em>mem>ples. 3 Answers ...
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TortoiseHg Apply a Patch

TortoiseHg allows you to e<em>mem>ail a patch file of your changes to so<em>mem>eone, but does it support applying patches? 4 Answers ...
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How do you stop Console fro<em>mem> popping up auto<em>mem>atically in Eclipse

I have a web application running in Eclipse with To<em>mem>cat. It has a few errors that <em>mem>ake the console popup every few seconds. How do I stop it fro<em>mem> auto<em>mem>atically popping up and taking focus? ...
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How to express infinity in Ruby?

... +1.0/0.0 =&a<em>mem>p;gt; Infinity NegativeInfinity = -1.0/0.0 =&a<em>mem>p;gt; -Infinity Co<em>mem>pleteInfinity = NegativeInfinity..PositiveInfinity =&a<em>mem>p;gt; -Infinity..Infinity *I've verified this in Ruby 1.8.6 and 1.9.2 share | ...
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Regex not operator

...e in that string : "(2001) (asdf) (dasd1123_asd 21.01.2011 zqge)(dzqge) na<em>mem>e (20019)" 2 Answers ...
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Re<em>mem>ove characters fro<em>mem> NSString?

I want to re<em>mem>ove the spaces, so the new string would be "ABCDEFG". 6 Answers 6 ...
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How do negated patterns work in .gitignore?

I a<em>mem> atte<em>mem>pting to use a .gitignore file with negated patterns (lines starting with !), but it's not working the way I expect. ...
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$(this) inside of AJAX success not working

I a<em>mem> trying to change so<em>mem>e old code which uses onclick so that I an use the $(this). The proble<em>mem> is that $(this) is not working when inside the success. Is there anyway to do this without setting it as a var. ...
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Split string based on regex

... I suggest l = re.co<em>mem>pile("(?&a<em>mem>p;lt;!^)\s+(?=[A-Z])(?!.\s)").split(s) Check this de<em>mem>o. share | i<em>mem>prove this answer | fol...