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How to see the changes between two commits without commits in-between?
How do you make git diff only show the difference between two commits, excluding the other commits in-between?
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Check if object is a jQuery object
Is there a fast way of checking if an object is a jQuery object or a native JavaScript object?
9 Answers
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Is there a foreach in MATLAB? If so, how does it behave if the underlying data changes?
Is there a foreach structure in MATLAB? If so, what happens if the underlying data changes (i.e. if objects are added to the set)?
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How to convert a factor to integer\numeric without loss of information?
...numeric or integer, I get the underlying level codes, not the values as numbers.
10 Answers
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What is a plain English explanation of “Big O” notation?
I'd prefer as little formal definition as possible and simple mathematics.
41 Answers
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Calling Java varargs method with single null argument?
If I have a vararg Java method foo(Object ...arg) and I call foo(null, null) , I have both arg[0] and arg[1] as null s. But if I call foo(null) , arg itself is null. Why is this happening?
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Vagrant error: NFS is reporting that your exports file is invalid
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Try using the known good versions of VirtualBox and Vagrant noted in Discourse as Your First Rails App:
Vagrant 1.1.2
VirtualBox 4.2.10
I was having the same issue on Mac (OS X 10.9 (Mavericks)), but rolling back to these versions seemed to fix it for me.
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What is the GAC in .NET?
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Right, so basically it's a way to keep DLLs globally accessible without worrying about conflicts. No more DLL Hell. Each architecture and version gets it's own place to live.
It also gets it own way to browse it in Explorer, so if y...
Why is i++ not atomic?
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i++ is probably not atomic in Java because atomicity is a special requirement which is not present in the majority of the uses of i++. That requirement has a significant overhead: there is a large cost in making an increment operation ...
What algorithms compute directions from point A to point B on a map?
...ing Dijkstra's once from source to dest, you start at each end, and expand both sides until they meet in the middle. This eliminates roughly half the work (2*pi*(r/2)^2 vs pi*r^2).
To avoid exploring the back-alleys of every city between your source and destination, you can have several layers of ma...