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Convert pem key to ssh-rsa format
...m assuming no password for the keys (which is bad).
Generate an RSA pair
All the following methods give an RSA key pair in the same format
With openssl (man genrsa)
openssl genrsa -out dummy-genrsa.pem 2048
In OpenSSL v1.0.1 genrsa is superseded by genpkey so this is the new way to do it (man...
Exit codes in Python
...
What you're looking for in the script is calls to sys.exit(). The argument to that method is returned to the environment as the exit code.
It's fairly likely that the script is never calling the exit method, and that 0 is the default exit code.
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Pandas percentage of total with groupby
... is a table of some kind, so 100 * x doesn't intuitively make sense (especially when some of the cells contain strings like AZ, ...).
– dhardy
Feb 6 '15 at 9:42
6
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How to check what version of jQuery is loaded?
... containing the version number.
If you get back a version number -- usually as a string -- then jQuery is loaded and that is what version you're working with. If not loaded then you should get back undefined or maybe even an error.
Pretty old question and I've seen a few people that have alrea...
SQL Server: Filter output of sp_who2
Under SQL Server, is there an easy way to filter the output of sp_who2? Say I wanted to just show rows for a certain database, for example.
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Generate list of all possible permutations of a string
How would I go about generating a list of all possible permutations of a string between x and y characters in length, containing a variable list of characters.
...
Retrieving Property name from lambda expression
...rce parameter is used so the compiler can do type inference on the method call. You can do the following
var propertyInfo = GetPropertyInfo(someUserObject, u => u.UserID);
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How do I get the localhost name in PowerShell?
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Don't forget that all your old console utilities work just fine in PowerShell:
PS> hostname
KEITH1
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Computational complexity of Fibonacci Sequence
...ll have depth n and intuitively figure out that this function is asymptotically O(2n). You can then prove your conjecture by induction.
Base: n = 1 is obvious
Assume T(n-1) = O(2n-1), therefore
T(n) = T(n-1) + T(n-2) + O(1) which is equal to
T(n) = O(2n-1) + O(2n-2) + O(1) = O(2n)
However, as ...
Changing the cursor in WPF sometimes works, sometimes doesn't
...deCursor:
Mouse.OverrideCursor = Cursors.Wait;
try
{
// do stuff
}
finally
{
Mouse.OverrideCursor = null;
}
This overrides the cursor for your application rather than just for a part of its UI, so the problem you're describing goes away.
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