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Is this the right way to clean-up Fragment back stack when leaving a deeply nested stack?
...tp://groups.google.com/group/android-developers/browse_thread/thread/d2a5c203dad6ec42
Essentially you have the following options
Use a name for your initial back stack state and use
FragmentManager.popBackStack(String name,
FragmentManager.POP_BACK_STACK_INCLUSIVE).
Use FragmentManager.getBackSta...
What is the difference between typeof and instanceof and when should one be used vs. the other?
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answered Jul 8 '11 at 14:30
Szymon WygnańskiSzymon Wygnański
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Was PreferenceFragment intentionally excluded from the compatibility package?
I'm looking to write preferences that can be applied to both 3.0 and pre-3.0 devices. Discovering that PreferenceActivity contains deprecated methods (although these are used in the accompanying sample code), I looked at PreferenceFragement and the compatibility package to solve my woes.
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How to parse a query string into a NameValueCollection in .NET
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edited Mar 30 '15 at 13:11
Carl Onager
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How to get Vim to highlight non-ascii characters?
...lsearch enabled) all other characters lying outside the ASCII range:
/[^\x00-\x7F]
This will do a negative match (via [^]) for characters between ASCII 0x00 and ASCII 0x7F (0-127), and appears to work in my simple test. For extended ASCII, of course, extend the range up to \xFF instead of \x7F us...
Find if variable is divisible by 2
.../ Will evaluate to true if the variable is divisible by 2
variable % 2 === 0
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How to Sign an Already Compiled Apk
... -keystore my-release-key.keystore -alias alias_name -keyalg RSA -keysize 2048 -validity 10000
then sign the apk using :
jarsigner -verbose -sigalg SHA1withRSA -digestalg SHA1 -keystore my-release-key.keystore my_application.apk alias_name
check here for more info
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Format XML string to print friendly XML string
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190
Use XmlTextWriter...
public static string PrintXML(string xml)
{
string result = "";
M...
How do I measure the execution time of JavaScript code with callbacks?
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user2362662user2362662
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Check if a given key already exists in a dictionary and increment it
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answered Jan 23 '09 at 14:38
dF.dF.
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