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Get current folder path
...location.
– dhruvin
Apr 21 '15 at 3:05
Perfect. This works independently for any application, especially when using St...
How to atomically delete keys matching a pattern using Redis
...ry in your Redis server, you'll run into the "too many elements to unpack" error. In that case, do:
for _,k in ipairs(redis.call('keys', ARGV[1])) do
redis.call('del', k)
end
As Kikito suggested.
share
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Sort a list by multiple attributes?
...|
edited Apr 24 '18 at 22:05
smci
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answered Nov...
Java generics type erasure: when and what happens?
...t;).
Despite that it makes generic arrays unusable and cause some strange errors for raw types:
List<String> l= List.<String>of("h","s");
List lRaw=l
l.add(new Object())
String s=l.get(2) //Cast Exception
it causes a lot of ambiguities as
void function(ArrayList<Integer> list...
Java dynamic array sizes?
...
answered Oct 30 '09 at 0:05
cletuscletus
562k152152 gold badges873873 silver badges927927 bronze badges
...
How do I enumerate the properties of a JavaScript object? [duplicate]
...wnPropertyNames(obj) is what you want if you are dealing with some sort of Error object (ex. TypeError) because the properties are non-enumerable.
– vossad01
Oct 24 '16 at 16:18
...
Python Dictionary Comprehension
...y:'your value here' for key in old_dict.keys()}
You're receiving a SyntaxError because when you write
d = {}
d[i for i in range(1, 11)] = True
you're basically saying: "Set my key 'i for i in range(1, 11)' to True" and "i for i in range(1, 11)" is not a valid key, it's just a syntax err...
find -exec with multiple commands
...
TinkerTinker
7,05011 gold badge1212 silver badges77 bronze badges
...
Create a list from two object lists with linq
...lue,
Change = p2.Value - p1.Value
}));
Although this won't error in the case where you have duplicate names in either set.
Some other answers have suggested using unioning - this is definitely not the way to go as it will only get you a distinct list, without doing the combining.
...
Select top 10 records for each category
...
If you are using SQL 2005 you can do something like this...
SELECT rs.Field1,rs.Field2
FROM (
SELECT Field1,Field2, Rank()
over (Partition BY Section
ORDER BY RankCriteria DESC ) AS Rank
FROM table
...