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What are the default access modifiers in C#?
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The default access for everything in C# is "the most restricted access you could declare for that member".
So for example:
namespace MyCompany
{
class Outer
{
void Foo() {}
class Inner {}
}
}
is equivalent to
namespace MyCompany
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Can I call an overloaded constructor from another constructor of the same class in C#?
...ll an overloaded constructor from another constructor of the same class in C#?
4 Answers
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Never seen before C++ for loop
I was converting a C++ algorithm to C#.
I came across this for loop:
12 Answers
12
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How to initialize a list of strings (List) with many string values
How is it possible to initialize (with a C# initializer) a list of strings? I have tried with the example below but it's not working.
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How can we generate getters and setters in Visual Studio?
...ft.com/en-us/library/z41h7fat.aspx for more useful code snippets in Visual C#
– Titus
Jun 22 '15 at 10:04
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ResourceDictionary in a separate assembly
... XAML:
If you know the other assembly structure and want the resources in c# code, then use below code:
ResourceDictionary dictionary = new ResourceDictionary();
dictionary.Source = new Uri("pack://application:,,,/WpfControlLibrary1;Component/RD1.xaml", UriKind.Absolute);
foreach (var item in d...
Func with out parameter
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In C# 4 (2010) and later (was not released when you wrote your answer) it is possible to mark T as contravariant, and V as covariant. However, since a parameter (output) of type U is passed by reference, U cannot be marked co- o...
Java's Interface and Haskell's type class: differences and similarities?
...y similar to the situation with operator overloading in languages like C++/C#, except more flexible and generalized.
Interfaces serve a similar purpose in OO languages, but the underlying concept is somewhat different; OO languages come with a built-in notion of type hierarchies that Haskell simply...
Kill some processes by .exe file name
... can I kill some active processes by searching for their .exe filenames in C# .NET or C++?
6 Answers
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Why can I pass 1 as a short, but not the int variable i?
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The first two are constant expressions, the last one isn't.
The C# specification allows an implicit conversion from int to short for constants, but not for other expressions. This is a reasonable rule, since for constants the compiler can ensure that the value fits into the target type, b...