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What are Aggregates and PODs and how/why are they special?
...yntax, etc.) please leave a comment, I'll edit.
This answer applies to C++03. For other C++ standards see:
C++11 changes
C++14 changes
C++17 changes
What are aggregates and why they are special
Formal definition from the C++ standard (C++03 8.5.1 §1):
An aggregate is an array or a class...
How to convert java.util.Date to java.sql.Date?
... Stack Overflow for many examples and explanations. Specification is JSR 310.
The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.
You may exchange java.time objects directly with your database. Use a JDBC driver compliant with JDBC 4.2 or later. No need for st...
How do getters and setters work?
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Dmitry Ginzburg
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answered Jan 10 '10 at 12:27
Paul CreaseyPaul Creasey
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Hashing a dictionary?
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edited Jul 26 '19 at 10:04
mit
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answered May ...
How to show a dialog to confirm that the user wishes to exit an Android Activity?
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In Android 2.0+ this would look like:
@Override
public void onBackPressed() {
new AlertDialog.Builder(this)
.setIcon(android.R.drawable.ic_dialog_alert)
.setTitle("Closing Activity")
.setMessage("Are you sure ...
How do I create a variable number of variables?
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307
You can use dictionaries to accomplish this. Dictionaries are stores of keys and values.
>...
Pure virtual function with implementation
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answered Jan 18 '10 at 21:00
Michael BurrMichael Burr
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App Launcher 应用启动器扩展:用于启动其他应用程序的强大工具,支持独立...
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版本
修改内容
1.0 (2020-04-16)
初始版本
2.0 (2020-04-29)
- 允许评估启动值和返回值- 作为独立进程或依赖进程启动
2.1 (2020-06-03)
添加了 MyAppName、MyPackageName
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Why does Javascript getYear() return 108?
Why does this javascript return 108 instead of 2008? it gets the day and month correct but not the year?
14 Answers
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How to create a simple map using JavaScript/JQuery [duplicate]
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Edit: Out of date answer, ECMAScript 2015 (ES6) standard javascript has a Map implementation, read here for more info: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Map
var map = new Object(); // or var map = {};
map[myKey1] = ...
